The formula to calculate pH slope is ΔpH/Δlog[H+], where ΔpH is the change in pH and Δlog[H+] is the change in the log concentration of hydrogen ions. This formula is used to determine the sensitivity of a pH electrode.
The pH of a solution is calculated using the formula pH = -log[H+]. Given [H+] = 5.1x10^-9 M, the pH is calculated as follows: pH = -log(5.1x10^-9) ≈ 8.29
The pH of a solution can be calculated using the formula pH = -log[H3O+]. Plugging in the concentration of H3O+ given (2.4 x 10^-10 M), we get pH = -log(2.4 x 10^-10) = 9.62. Therefore, the pH of this solution is 9.62.
The pH of a solution can be calculated using the formula pH = -log[H+]. Plugging in the value of [H+] = 2.3 x 10^-4 gives a pH of 3.64.
The pH of an aqueous solution with an H+ concentration of 0.00097 M is 2.01. The pH is calculated using the formula pH = -log[H+].
pH = pKa + log([A-]/[HA])
pH is the negative log of the hydronium ion concentration. It seems a little grandiose to call this a "formula", but here you go: pH = -log[H3O+]
The formula to calculate pH slope is ΔpH/Δlog[H+], where ΔpH is the change in pH and Δlog[H+] is the change in the log concentration of hydrogen ions. This formula is used to determine the sensitivity of a pH electrode.
The pH of a solution can be calculated using the formula pH = -log[H+]. Substituting the given H+ concentration (3.7x10-6) into the formula gives pH = -log(3.7x10-6) ≈ 5.43. Therefore, the pH of the solution is approximately 5.43.
-log [h30+]
pH=-log(H+)
pH = - log [H3O+]. It is the negative logarithm of the hydronium ion concentration.
Let ROH represent the alcoholROH <==> RO^- + H+ Ka = [H+][RO-]/[ROH] Solve for [H+] and take the negative log to get the pH
pH = -log[H+] where H+ equals the concentration of hydrogen ions in a given solution.
The pH of a solution is calculated using the formula pH = -log[H+]. In this case, the hydronium ion concentration is 0.0002 M, so the pH would be -log(0.0002) ≈ 3.7.
The pH of the solution can be calculated using the formula: pH = -log[H3O+]. Substituting the given value of [H3O+] = 2 x 10^-4M into the formula, pH = -log(2 x 10^-4) = 3.7. Therefore, the pH of the solution is 3.7.
The pH of a solution can be calculated using the formula pH = -log[H+]. Given that the hydronium ion concentration is 10^-1 M, the pH of the solution is pH = -log(10^-1) = 1. So, the pH of the solution is 1.