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In nature, the Lewis structure for oxygen exists this way so it could react with other elements and in nature, it is a gas so it exists as O2 . As you can see, O2, each oxygen is connected by a single bond, each gets two octets, and on the bottom of each O, each O has one unpaired electron. Oxygen is set up this way in nature as its Lewis structure so it could react with other elements.

.. ..:O-O:. .

Just how in nature, e.g., the Lewis structure for Nitrogen (gas element, therefore, N2) exists this way with a triple bond:

:N≡N:

Is there a reason you think that your two lone electrons don't form a pi bond and create a double bond? (which it does) Therefore satisfying the octet rule.

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13y ago
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6mo ago

The Lewis structure of O2, dioxygen, consists of two oxygen atoms bonded together by a double bond. Each oxygen atom has six valence electrons, resulting in a total of 12 valence electrons in the molecule.

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13y ago

Heres a pic of it,

http://picsdigger.com/image/fefc9303/

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15y ago

O=O with the other six dots surrounding the O's. The oxygen share a double bond in the middle.

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12y ago

H-O-O-H

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Q: What does the Lewis structure of O2 look like?
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What would a picture of o2 bonding with o2 look like?

O=O The Lewis dot structure without the lone pairs of electrons.


What is the Lewis structure of 3O2?

The Lewis structure of O2 is a double bond between the two oxygen atoms with two lone pairs on each oxygen atom. Thus, the Lewis structure of 3O2 would have three separate O2 molecules with a double bond and two lone pairs on each oxygen atom in each molecule.


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There are two bonds shown in the Lewis structure of O2, one single bond between the two oxygen atoms. Each oxygen atom satisfies the octet rule by sharing two electrons.


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The Lewis dot structure of O2 has a double bond between the two oxygen atoms, each oxygen atom has 6 valence electrons. The Lewis dot structure of N2 has a triple bond between the two nitrogen atoms, each nitrogen atom has 5 valence electrons.


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