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Write 0.081778 correct to 2 significant figures?

0.081778 to two significant figures is 0.082


What is 147.658 correct to 2 significant figures?

147.658 to two significant figures is 150.


What 248 correct to 2 significant figures?

Nothing


How many significant figures in 17.000?

The correct answer is 2. The three zeros between the decimal point and the 1 are place holders but they are NOT significant digits. See, for example, the Wikipedia link.


When 64.4 is divided by 2.00 what is the correct number of significant figures in the result?

32.2


What are the rules in expressing the correct number significant figures?

all non zero digits are significant .2.zeroes betweenother significant.


If the mass of an electron is 9.10939 x 10-31 then show 1 2 3 and 4 of its significant figures?

Significant figures are very important when it comes to calculations. If the mass of an electron is 9.10939 x 10-31 then its significant figures are: 9 x 10^-31( correct 1 significant figure), 9.1 x 10^-31 kg ( correct to 2 significant figures), 9.11 x 10^-31 (correct to 3 significant figures), and 9.109 x 10^-31 (correct to 4 significant figures).


How many significant figures in 0.56?

2 significant figures


How many significant figures in this number 0.025?

There are two significant figures in 0.025.


How many significant figures does 2090 have?

there are 2 significant figures in 21000 2 & 1 are the significant figures.


When 2610 11.7 0.22 are added the answer to the correct number of decimal places is?

The correct answer depends on what is known about the number 2610. If it is known to be correct to 3 significant figures, the correct answer is 2620. If it is known to be correct to 4 significant figures, the correct answer is 2622. If all the numbers are known to be accurate to at least 2 decimal places then the correct answer is 2621.92


Would it be correct to record the length of the string as 0.48 decimeters or 0.4800 decimeters?

0.48 has 2 significant figures and 0.4800 has 4 significant figures. The correct answer would depend on the device used to measure the string, and on the precision of that instrument.