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Characteristic function of any borel set is an example of simple Borel function

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13y ago

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Give an example of a subset of R that is not a Borel set?

An example is given here: http://en.wikipedia.org/wiki/Non-Borel_set Any set that is easy to think of will be a Borel set, so an example of a non-Borel set will be complicated. Another approach: All Borel sets are Lebesgue measurable. The axiom of choice can be used to give an example of a non-measurable set, and this set will also be a non-Borel set. See http://en.wikipedia.org/wiki/Non-measurable_set = =


Is the inverse image of a measurable set under a continuous map measurable?

Yes, the inverse image of a measurable set under a continuous map is measurable. If ( f: X \to Y ) is a continuous function and ( A \subseteq Y ) is a measurable set, then the preimage ( f^{-1}(A) ) is measurable in ( X ). This property holds for various types of measurable spaces, including Borel and Lebesgue measurability. Thus, continuous functions preserve the measurability of sets through their inverse images.


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Louis Borel's birth name is Lodewijk Borel.


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Petrus Borel was born in 1809.


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