A typical iron pulls around 9-12 amps when in use. It's important to check the specific amp requirement of your iron to ensure it matches the capacity of your electrical circuit.
At a specific voltage the higher the amperage the higher the rated horsepower of the motor. You will see the amperage rating used when manufactures sell hand tools. A saw that draws 12 amps, it is stated, is better than the saw that draws 9 amps. As the question stands a comparison can not be made between voltage and amps.
Batteries are normally specified in ampere hours. A 12 v battery could be specified as 14 A-h or 14 ampere-hours, which means 14 amps for 1 hour, or 1.4 amps for 10 hours. In other words it produces less current for a longer time. A 9 watt bulb takes ¾ amp in theory, so it should last 14/¾ hours on that battery, that is 14 x 4 / 3 hours, 18 hours. Or two of the same bulbs for 9 hours, etc.
A standard home outlet in North America is 15 amps protecting a #14 copper conductor. The circuit should only be loaded to 80% of the circuits capacity. Watts = Amps x Volts = 15 x 120 = 1800. 1800 x .80 = 1440. As you can see a standard outlet does not meet the requirements, with or without the de-rate factor, that the sauna manufacturer recommends. The amperage that the sauna needs is, Amps = Watts/Volts. Amps = 2035/120 = 16.9 or (17 amps). The circuit for the sauna would require a single pole 20 amp breaker feeding a #12 copper conductor which is rated for 20 amps. The amperage rating of the sauna is just over the 80% by .9 of an amp. This amperage is close enough that it would be passed by an electrical inspector if this project were to be inspected.
To calculate power, multiply voltage (9 volts) by current (0.02 amps): 9 volts * 0.02 amps = 0.18 watts.
A typical iron pulls around 9-12 amps when in use. It's important to check the specific amp requirement of your iron to ensure it matches the capacity of your electrical circuit.
You cannot compare these two totally different things. As far as amperage the charger puts out more amps if it is an auto battery charger and also puts out 12 volts. If you are talking about a 9 volt battery charger then the battery may or may not be more powerful, it depends on how many mii-amps the charger is putting out.
Your question is similar to: "Is an apple more powerful than an orange?" You are comparing two different parameters. Electric Power = Volts multiplied by Amperes = Volt-Amps. To know which drill is more powerful, you need to compare the Volt-Amps of each drill with the other one. If the battery voltage is the same for both drills (it probably is not), then the one with the highest motor current rating SHOULD be the most powerful. However, manufacturers tend to fudge some on their ratings. When they say "This is a 9 Amp drill", often it is not clear or not defined what they mean. Is the battery rated for a 9 Amp output, or is the motor rated to use 9 Amps maximum, or 9 Amps average, or are the wires running from the battery to the motor rated for 9 Amps? You see what I mean. Electric power cannot be measured in Amps or in Volts, but must be a combination of the two (Volt-Amps, or Watts, or Horsepower, or some known and well-defined power quantity).
A #14 copper wire rated at 15 amps is the minimum size wire for a 15 amp receptacle.
At a specific voltage the higher the amperage the higher the rated horsepower of the motor. You will see the amperage rating used when manufactures sell hand tools. A saw that draws 12 amps, it is stated, is better than the saw that draws 9 amps. As the question stands a comparison can not be made between voltage and amps.
To calculate the time it takes for 9 coulombs to pass a current of 3 amps, you can use the formula: time = charge / current. Plugging in the values, time = 9 coulombs / 3 amps = 3 seconds. So, it would take 3 seconds for 9 coulombs to pass a current of 3 amps.
i have samsung 1.5 split sc...n it consume 9 to 10 amp...so i guess its normal 12 amp ...
Batteries are normally specified in ampere hours. A 12 v battery could be specified as 14 A-h or 14 ampere-hours, which means 14 amps for 1 hour, or 1.4 amps for 10 hours. In other words it produces less current for a longer time. A 9 watt bulb takes ¾ amp in theory, so it should last 14/¾ hours on that battery, that is 14 x 4 / 3 hours, 18 hours. Or two of the same bulbs for 9 hours, etc.
A standard home outlet in North America is 15 amps protecting a #14 copper conductor. The circuit should only be loaded to 80% of the circuits capacity. Watts = Amps x Volts = 15 x 120 = 1800. 1800 x .80 = 1440. As you can see a standard outlet does not meet the requirements, with or without the de-rate factor, that the sauna manufacturer recommends. The amperage that the sauna needs is, Amps = Watts/Volts. Amps = 2035/120 = 16.9 or (17 amps). The circuit for the sauna would require a single pole 20 amp breaker feeding a #12 copper conductor which is rated for 20 amps. The amperage rating of the sauna is just over the 80% by .9 of an amp. This amperage is close enough that it would be passed by an electrical inspector if this project were to be inspected.
Ohm's Law: Voltage = Amperes times Resistance 9 volts = amps * 10 ohms amps = .9
To calculate power, multiply voltage (9 volts) by current (0.02 amps): 9 volts * 0.02 amps = 0.18 watts.
set your voltage first to around 4-6v for rotary 8-9 for regular guns and thenadjustthe amps until the gun sounds right.