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What is the approximate energy of a photon having a frequency of 4 100000000 Hz?
Wiki User
∙ 13y ago
E=h*f
h is Planck's constant, which is equal to 6.62 x 10-34 J . s.
f is the frequency in Hz.
Multiplication of two numbers together is left as an exercise to the student.
3.2 x 10-18 J
acutual answer on The Question is 4.3 x 10-19J
Wiki User
∙ 14y ago
The energy of a photon can be calculated using the equation E = hf, where h is the Planck constant (6.626 x 10^-34 J*s) and f is the frequency. Plugging in the values, the energy of a photon with a frequency of 4 x 10^8 Hz is approximately 2.65 x 10^-25 Joules.
Wiki User
∙ 10y agoThe energy of a photon of frequency 1.25 x 10^6 Hz can be calculated using the relation E = hf, where E is the energy in Joules, h is Planck's constant 6.63 x 10^-34 m^2 kg / s, and f is the frequency in cycles per second (Hz). The energy of this photon is 8.28 x 10^-28 J.
Wiki User
∙ 13y agoTo calculate this we use the de Broglie equation f=E/h, where f is the frequency, E is the energy of the particle and h is Planck's constant.
The energy of a photon with a frequency of 4100000000 Hz then equals:
E= f*h = 4100000000 Hz * 6.626068 * 10^-34 Js = 2.71*10^-24 J
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The energy of a photon can be calculated using the formula E = hf, where h is Planck's constant (6.626 x 10^-34 J·s) and f is the frequency of the photon. Plugging in the values, the energy of a photon with a frequency of 4 x 10^7 Hz is approximately 2.65 x 10^-26 Joules.
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The frequency of a photon can be calculated using the formula E = hf, where E is the energy of the photon, h is Planck's constant (6.626 x 10^-34 Js), and f is the frequency. Rearranging the formula to solve for frequency gives f = E/h. Substituting the given energy value of 5 x 10^-24 J gives a frequency of approximately 7.55 x 10^9 Hz.
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What is the approximate energy of a photon having a frequency of a 4 x 107?
To calculate the energy of a photon, we can use the equation E = hf, where E is the energy, h is Planck's constant (6.626 x 10^-34 Js), and f is the frequency of the photon. Plugging in the values: E = 6.626 x 10^-34 Js * 4 x 10^7 Hz = 2.65 x 10^-26 J. Therefore, the approximate energy of the photon is 2.65 x 10^-26 joules.
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