54.93805
The atomic weight of manganese (Mn) is 54,938 044(3).
The atomic mass of potassium permanganate (KMnO₄) can be calculated by summing the atomic masses of its constituent elements: potassium (K), manganese (Mn), and oxygen (O). The approximate atomic masses are 39.1 g/mol for K, 54.9 g/mol for Mn, and 16.0 g/mol for each of the four oxygen atoms. Therefore, the total atomic mass of KMnO₄ is about 158.0 g/mol.
Manganese is a metal element. Atomic mass of it is 55.
To calculate the molar mass of Mn₂Se₇, you need the atomic masses of manganese (Mn) and selenium (Se). The molar mass of Mn is approximately 54.94 g/mol, and for Se, it is about 78.96 g/mol. Thus, the molar mass of Mn₂Se₇ is calculated as follows: (2 × 54.94 g/mol) + (7 × 78.96 g/mol) = 109.88 g/mol + 552.72 g/mol = 662.60 g/mol. Therefore, the molar mass of Mn₂Se₇ is approximately 662.60 g/mol.
To calculate the relative atomic mass of an element (which is by its definition an average), you need the mass number and relative abundance of each isotope present. Suppose we have the following data from the mass spectrometer: first isotope mn X, abundance A% second isotope mn Y, abundance B% third isotope mn Z, abundance C%. Then ram = (A/100 x X) + (B/100 x Y) + (C/100 x Z) If there are more than 3 isotopes, just do the same for each one and add all the expressions together.
Manganese (Mn)
The atomic weight of manganese (Mn) is 54,938 044(3).
Manganese or Mn has an atomic number of 25 (25 protons). The stable atom has 30 neutrons, so the stable atomic mass is 55 amu. The mass for one of its isotopes depends on how many neutrons it has. For instance, the next most stable isotope of Mn is Mn53 with only 28 neutrons so it has an atomic mass of 53 amu.
The atomic mass of potassium permanganate (KMnO₄) can be calculated by summing the atomic masses of its constituent elements: potassium (K), manganese (Mn), and oxygen (O). The approximate atomic masses are 39.1 g/mol for K, 54.9 g/mol for Mn, and 16.0 g/mol for each of the four oxygen atoms. Therefore, the total atomic mass of KMnO₄ is about 158.0 g/mol.
To find the mass of 1.02×10^24 atoms of Mn, you need to calculate the atomic mass of Mn from the periodic table (54.938045 g/mol). Then, divide the number of atoms by Avogadro's number to get moles, and finally multiply by the atomic mass to get the mass in grams. The mass of 1.02×10^24 atoms of Mn would be approximately 94.64 grams.
Manganese is a metal element. Atomic mass of it is 55.
The molar mass is:39,0983 (atomic weight of K) + 54,938044 (idem for Mn) + (15,999 . 4 for O) = 157,432344 g
To calculate the molar mass of Mn₂Se₇, you need the atomic masses of manganese (Mn) and selenium (Se). The molar mass of Mn is approximately 54.94 g/mol, and for Se, it is about 78.96 g/mol. Thus, the molar mass of Mn₂Se₇ is calculated as follows: (2 × 54.94 g/mol) + (7 × 78.96 g/mol) = 109.88 g/mol + 552.72 g/mol = 662.60 g/mol. Therefore, the molar mass of Mn₂Se₇ is approximately 662.60 g/mol.
The atomic radius of manganese (Mn) is approximately 127 picometers (pm).
To calculate the relative atomic mass of an element (which is by its definition an average), you need the mass number and relative abundance of each isotope present. Suppose we have the following data from the mass spectrometer: first isotope mn X, abundance A% second isotope mn Y, abundance B% third isotope mn Z, abundance C%. Then ram = (A/100 x X) + (B/100 x Y) + (C/100 x Z) If there are more than 3 isotopes, just do the same for each one and add all the expressions together.
Manganese is a metal element. Atomic number of it is 25.
In it's most stable form, 55 is its atomic mass. 55 overall - 25 protons = 30 neutrons