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You can solve this problem using Bernoulli's Equation P1/y + z1 + v2/1/2g = P2/y + z2 + v2/2/2g However, This will only br valid for incompressable fluids, and the specific weight of the fluid is the same at both ends. There can't be any mechanical devices between the two ends, and no energy can be tranferred out or lost by friction.

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16y ago
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1mo ago

The constant force required to pump water through a pipe depends on factors like pipe diameter and pressure head. Given the information provided, it's not possible to determine the force in Newton meters. If the flow rate is doubled to 2 liters per second, the force required typically increases but does not necessarily double, as it also depends on factors like friction losses in the pipe.

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15y ago

You need to know the distance from the pipe to the paddle to ascertain the velocity. Force = mass of water x square of the velocity assuming it is stopping at the paddle. The force would quadruple if it were following twice as fast since the force is proportional to the velocity squared.

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Q: What is the constant force Nm and speed of water flowing through a 20 mm pipe at 1 liter per second and does the force double if the flow is doubled?
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Doubled is already the past tense form of double.


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