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What element is reduced in this reaction cr2o7 3hno2 5h-2cr3 3no3 4h2o?
In this reaction, chromium (Cr) is being reduced from a +6 oxidation state in Cr2O7 to a +3 oxidation state in 2Cr3+.
Reaction between potassium dichromate and iron sulphate?
When potassium dichromate reacts with iron (II) sulfate in an acidic solution, a redox reaction occurs. The dichromate ions are reduced to chromium (III) ions, while iron (II) ions are oxidized to iron (III) ions. The overall reaction is 6Fe2+ + Cr2O72- + 14H+ -> 6Fe3+ + 2Cr3+ + 7H2O.
Write a balanced redox equation for the oxidation of chloride to chlorine by acidified potassium dichromate?
K2Cr2O7 + 4H2SO4 + 6Cl-1----------> K2SO4 + Cr2(SO4)3 + 3Cl2 + 4H2O + 3O-2
What is the Reaction of k2cr2o7 with so2?
The reaction of K2Cr2O7 with SO2 in acidic medium results in the formation of chromium(III) sulfate (Cr2(SO4)3), sulfuric acid (H2SO4), and water. This reaction involves the reduction of Cr(VI) in K2Cr2O7 to Cr(III) in chromium(III) sulfate.
Chemical reaction between iron and potassium dichromate?
When iron reacts with potassium dichromate, iron(II) ion is oxidized to iron(III) ion by dichromate, which gets reduced to chromium(III) ion. The balanced chemical equation for this reaction is: 6 Fe^2+ + 14 H^+ + Cr2O7^2- --> 6 Fe^3+ + 2 Cr^3+ + 7 H2O
Disproportionation of chromium oxide in acid?
6CrO2 (aq) + 10 H+ (aq) --> Cr O72- (aq) + 4 Cr3+ (aq) + 5H2O (l)
What is the correct formula for the ionic compound formed between chromium and chloride?
The correct formula for the ionic compound formed between chromium and chloride is CrCl3. This is because chromium has a 3+ charge and chloride has a 1- charge, so it takes three chloride ions to balance the charge of one chromium ion.
What is the reaction between dichromate and iodide?
When dichromate reacts with iodide ions in acidic solution, chromium is reduced from a +6 oxidation state to a +3 oxidation state, and iodide is oxidized to iodine. The balanced equation for this reaction is: Cr2O7 2- + 6I- + 14H+ → 2Cr3+ + 3I2 + 7H2O
What is the reaction of acidified pot dichromate with Hydrogen Sulphide?
When acidified potassium dichromate (K2Cr2O7) reacts with hydrogen sulfide (H2S), it forms chromium(III) sulfide (Cr2S3), sulfur dioxide (SO2), and water (H2O). The orange dichromate solution turns green as Cr2S3 is formed. This reaction is often used as a test for the presence of hydrogen sulfide gas.
What is the new oxidation number for cr2o7-2 plus 8h plus 3so3-2 2cr3 plus 3sov-2 plus 4h20?
oxidation number of S is +6.It oxidize into SO4 ^-2
What is the net ionic equation for chromium sulfate and ammonium carbonate Cr2SO43 NH42CO3also what are the spectator ions of this equation?
net ionic equation only has the ions that become a precipitate: 2Cr3+(aq)+3CO32-(aq)--->Cr2(CO3)3(s) spectator ions are the ones that do not make a precipitate: SO42-,NH4+ no precipitate(combines to form another aqueous solution)=no reaction. hope this helps
How many milliliters of 0.325 N HCl are nescessary to reduce 37.6 milliliters of a 0.526 N solution of K2Cr2O7?
First:Comparing the electropotential values of both redox couples (being equal, see below 1. and 2.)AND considering that Cl2 gas might escape the mixture giving toxic fumes,it does NOT look a good titration method.2Cl- --> Cl2,g + 2e- (delta)Eo= -1.36VCr2O72- + 14H+ + 6e- --> 2Cr3+ + 7H2O (delta)Eo= +1.36VSecond:There is no exact answer possible because the titration end point can never be established, you'll never know when the last Cl2 is escaped, and there is no sharp (sudden) change in colour, and the reaction at the endpoint is very slow.Third: The answer is 60.9 mLThe equivalent point (theorethical end point) can be calculated as follows:mEq reductor (HCl) = mEq oxidator (K2Cr2O7)0.325 (mEq/mL HCl) * VHCl (mL) = 0.526 (mEq/mL K2Cr2O7) * 37.6 (mL K2Cr2O7) So VHCl (mL) = 0.526 (mEq/mL K2Cr2O7) * 37.6 (mL K2Cr2O7) / 0.325 (mEq/mL HCl) = 60.854 = 60.9 mL
