You can use De' Broglie's equation. I think it is wavelength = plank's constant/mass of the object *velocity.
velocity is unknown in this case, m= 154g and wavelength is 0.450*10-9
0.450*10-9 = look up the value of plank's constant/ 0.145 kg* Velocity.
Rearrange the equation to get velocity of an object.
the wavelength of its associated wave, known as the de Broglie wavelength. This relationship is expressed by the de Broglie equation: λ = h / p, where λ is the de Broglie wavelength, h is the Planck constant, and p is the momentum of the particle.
The de Broglie wavelength formula is given by λ = h / p, where λ is the wavelength, h is Planck's constant, and p is the momentum of the particle. It relates the wavelength of a particle to its momentum, demonstrating the wave-particle duality in quantum mechanics.
Louis de Broglie
Electrons will travel fastest when hitting uranium at a specific wavelength corresponding to their maximum kinetic energy, which is determined by the energy of the incoming electrons and the properties of uranium. This wavelength can be calculated using the de Broglie wavelength formula involving the electron's energy and momentum.
Electrons, like light and sound, exhibit wave-particle duality. They have a property called quantum mechanical wavelength, defined by de Broglie's equation, that links their momentum with their wavelength. This wavelength is responsible for interference effects when electrons interact with each other or with other particles.
The de Broglie Wavelength of a mosquito can be calculated using a specific formula. For this example, the wavelength is 2.8 to the 28th power meters.
the wavelength of its associated wave, known as the de Broglie wavelength. This relationship is expressed by the de Broglie equation: λ = h / p, where λ is the de Broglie wavelength, h is the Planck constant, and p is the momentum of the particle.
The de Broglie wavelength is a concept in quantum mechanics that describes the wave nature of a particle. It represents the wavelength associated with a particle's momentum, showing that particles such as electrons have both wave and particle-like properties. The de Broglie wavelength is inversely proportional to the momentum of the particle.
The de Broglie wavelength of a photon remains constant as its velocity increases because a photon always travels at the speed of light in a vacuum. The wavelength of light is determined by its frequency according to the equation λ = c / f.
1924
It is electron since wavelength = h/(mv), and since proton's mass > electron's mass, electron's wavelength is longer.
The de Broglie wavelength of an atom at absolute temperature T K can be calculated using the formula λ = h / (mv), where h is Planck's constant, m is the mass of the atom, and v is the velocity of the atom. At higher temperatures, the velocity of atoms increases, leading to a shorter de Broglie wavelength.
The De Broglie wavelength is commonly used in the field of quantum mechanics to describe the wave-like behavior of particles, such as electrons or atoms. It provides insight into the wave-particle duality of matter, where particles can exhibit both wave-like and particle-like properties.
The de Broglie wavelength formula is given by λ = h / p, where λ is the wavelength, h is Planck's constant, and p is the momentum of the particle. It relates the wavelength of a particle to its momentum, demonstrating the wave-particle duality in quantum mechanics.
No, they don't have de-broglie wavelength since this concept is valid for substances having some mass. This concept is mainly used to calculate the wavelength of electrons. The photons are just energy packets and they are not matter and don't have weight. Therefore, they don't have de-broglie wavelength
The de Broglie equation, which relates the wavelength of a particle to its momentum, is derived from the concept of wave-particle duality in quantum mechanics. It was proposed by Louis de Broglie in 1924, suggesting that particles, such as electrons, can exhibit wave-like properties. The equation is h/p, where is the wavelength, h is the Planck constant, and p is the momentum of the particle.
Yes, a photon does have a de Broglie wavelength, which is given by λ = h/p, where h is Planck's constant and p is the photon's momentum. Photons exhibit both wave-like and particle-like properties.