Wiki User
∙ 12y agoYou can use De' Broglie's equation. I think it is wavelength = plank's constant/mass of the object *velocity.
velocity is unknown in this case, m= 154g and wavelength is 0.450*10-9
0.450*10-9 = look up the value of plank's constant/ 0.145 kg* Velocity.
Rearrange the equation to get velocity of an object.
Wiki User
∙ 14y agoTo calculate the de Broglie wavelength, you can use the formula λ = h / mv, where λ is the wavelength, h is Planck's constant (6.626 x 10^-34 m^2 kg / s), m is the mass of the Baseball, v is the velocity. Plugging in the values, you can find the de Broglie wavelength of the baseball.
Wiki User
∙ 12y ago=1.08×10−34
the wavelength of its associated wave, known as the de Broglie wavelength. This relationship is expressed by the de Broglie equation: λ = h / p, where λ is the de Broglie wavelength, h is the Planck constant, and p is the momentum of the particle.
The de Broglie wavelength formula is given by λ = h / p, where λ is the wavelength, h is Planck's constant, and p is the momentum of the particle. It relates the wavelength of a particle to its momentum, demonstrating the wave-particle duality in quantum mechanics.
Louis de Broglie
Electrons will travel fastest when hitting uranium at a specific wavelength corresponding to their maximum kinetic energy, which is determined by the energy of the incoming electrons and the properties of uranium. This wavelength can be calculated using the de Broglie wavelength formula involving the electron's energy and momentum.
Electrons, like light and sound, exhibit wave-particle duality. They have a property called quantum mechanical wavelength, defined by de Broglie's equation, that links their momentum with their wavelength. This wavelength is responsible for interference effects when electrons interact with each other or with other particles.
The de Broglie Wavelength of a mosquito can be calculated using a specific formula. For this example, the wavelength is 2.8 to the 28th power meters.
the wavelength of its associated wave, known as the de Broglie wavelength. This relationship is expressed by the de Broglie equation: λ = h / p, where λ is the de Broglie wavelength, h is the Planck constant, and p is the momentum of the particle.
The de Broglie wavelength is a concept in quantum mechanics that describes the wave nature of a particle. It represents the wavelength associated with a particle's momentum, showing that particles such as electrons have both wave and particle-like properties. The de Broglie wavelength is inversely proportional to the momentum of the particle.
The de Broglie wavelength of a photon remains constant as its velocity increases because a photon always travels at the speed of light in a vacuum. The wavelength of light is determined by its frequency according to the equation λ = c / f.
1924
The de Broglie wavelength is inversely proportional to the mass of the particle. Since a proton is much more massive than an electron, it will have a shorter de Broglie wavelength at the same speed.
The de Broglie wavelength of an atom at absolute temperature T K can be calculated using the formula λ = h / (mv), where h is Planck's constant, m is the mass of the atom, and v is the velocity of the atom. At higher temperatures, the velocity of atoms increases, leading to a shorter de Broglie wavelength.
The De Broglie wavelength is commonly used in the field of quantum mechanics to describe the wave-like behavior of particles, such as electrons or atoms. It provides insight into the wave-particle duality of matter, where particles can exhibit both wave-like and particle-like properties.
The de Broglie wavelength formula is given by λ = h / p, where λ is the wavelength, h is Planck's constant, and p is the momentum of the particle. It relates the wavelength of a particle to its momentum, demonstrating the wave-particle duality in quantum mechanics.
The de Broglie wavelength of one photon is inversely proportional to its momentum. Since a photon's momentum is given by its energy divided by the speed of light, the de Broglie wavelength of one photon is equal to Planck's constant divided by the photon's momentum.
Yes, a photon does have a de Broglie wavelength, which is given by λ = h/p, where h is Planck's constant and p is the photon's momentum. Photons exhibit both wave-like and particle-like properties.
The de Broglie wavelength for macroscopic objects is extremely tiny due to their large mass and momentum, making it impractical to observe in daily life. Additionally, interactions with the environment cause decoherence, effectively destroying any quantum effects on a macroscopic scale.