550/25 = 22 grams per cc
The density of the object is calculated by dividing the mass (550 g) by the volume it displaces (25 mL). However, since the units need to be consistent, 25 mL needs to be converted to cubic centimeters (cm3) since 1 mL is equal to 1 cm3. Thus, the density of the object is 22 g/cm3.
The density is 0,78 g/cm3.
The density of the rock can be calculated by dividing the mass of the rock (127g) by the volume of water it displaces (32.1 mL). The density of the rock is 3.95 g/mL.
To find the density of floating objects, you need to measure the mass of the object and the volume of water it displaces when floating. The density can then be calculated by dividing the mass of the object by the volume of water displaced.
If a part of a specimen floats in water, it likely has a lower density than water. The density of an object is determined by its mass and volume. Therefore, the part of the specimen that is floating likely has a volume that displaces enough water to support its mass, resulting in it floating.
-- If the object floats in water, then its density is less than the density of water. -- If the object sinks in water, then its density is more than the density of water. -- If the object floats in air, then its density is less than the density of air. -- If the object sinks in air, then its density is less than the density of air.
To find the density, divide the mass of the object by the volume of water it displaces. In this case, the density of the object would be 5 grams per milliliter (10 grams / 2 milliliters).
The density of the object can be calculated using the formula: Density = Mass/Volume. In this case, the mass of the object is 9.0 grams and it displaces 13 cm3 of water. Thus, the density of the object is 9.0g / 13 cm3 = 0.69 g/cm3.
To calculate the density of the object, you need to divide the mass of the object by the volume of water it displaces. Since water has a density of 1 g/mL, 4 millimeters of water is equal to 4 grams per square centimeter. Therefore, the density of the object would be 20 g / 4 cm^3 = 5 g/cm^3.
the specific gravity is how the density of the object compares to the density of water. Water's density is 1gram per milliliter. We just need to figure out the density of the object. The object is .8 kg and it displaces 500mL of water, so the density is the mass divided by the volume. Since the density of water is given in grams, we have to convert the objects mass from kg to g and then we can get the density. .8kg * 1000g/kg = 800 grams so, 800g/500ml = 1.6grams/mL this is the density. So divide the density of your object by the density of water, which is 1g/mL, you get 1.6 as the specific gravity. This means the object is 1.6 times more dense than water.
the specific gravity is how the density of the object compares to the density of water. Water's density is 1gram per milliliter. We just need to figure out the density of the object. The object is .8 kg and it displaces 500mL of water, so the density is the mass divided by the volume. Since the density of water is given in grams, we have to convert the objects mass from kg to g and then we can get the density. .8kg * 1000g/kg = 800 grams so, 800g/500ml = 1.6grams/mL this is the density. So divide the density of your object by the density of water, which is 1g/mL, you get 1.6 as the specific gravity. This means the object is 1.6 times more dense than water.
It is 2.5 grams per mL.
An object will float in water if its density is less than the density of water, which is 1 g/cm^3. This means that the weight of the object is less than the weight of the water it displaces, allowing it to float.
The density is 0,78 g/cm3.
Object B will displace more water because it has a higher density compared to object A. Displacement of water is determined by the density of the object, not its mass.
If an object floats in water, we can immediately conclude that it is less dense than the water. So, we've already gained a bit of information. But can we learn more? Yes. We can further "ballpark" our estimate of the object's density through additional observation and deduction. About how much of the object is submerged? If, say, 75 percent of the object is under water, we can then say that its relative density -- that is, its specific gravity -- is about 0.75. In other words, it has a density of 0.75 grams per milliliter or, equivalently, 0.75 grams per cubic centimeter. (Note that the density of water is 1.00 gram per milliliter.) But can we do better? I think so. If we measure the volume of water displaced by the object when it is placed into the container of water, we can calculate the weight of the object, because its weight will be equal to the weight of the water it displaces. If the floating object displaces, say, 100 milliliters of water, then we know it weighs 100 grams, because, as noted above, the density of water is one gram per milliliter. But we're not done. To calculate an object's density, we must know its volume as well as its mass. From the measurement above, we know the object's weight , but we don't know its volume, mainly because of its irregular shape. But if we carefully push the object completely under water, it will displace an amount of water equal to its volume. Let's say that when we submerge the object fully, it displaces 130 milliliters of water. We therefore conclude that its volume is 130 milliliters, which is equal to 130 cubic centimeters. Since the object weighs 100 grams and has a volume of 130 cubic centimeters, its density is 100 grams/130 cubic centimeters = 0.769 g/cm3.
It's difficult to tell what you are asking. If the question is concerned with the bouyancy of the object, it will sink if it first displaces its volume of water, or will float if it first displaces its weight in water. Since density is mass per unit volume, objects with an average density greater than water will sink.
The object would float in fresh water since its density is lower than that of water (1.0 g/mL). The object displaces an amount of water equal to its weight, which is less than the weight of water it displaces, causing it to float.