tetrahedral
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∙ 13y agoThe Lewis dot structure for BrO3 -1 consists of Br (Bromine) at the center, with one double bond and two single bonds to O (Oxygen) atoms. One of the oxygen atoms will have a lone pair of electrons. The overall charge of the ion is -1.
The electron valence shell has 1 electron.
The electron has a charge of -1; but the electron has a mass.
The ratio of the specific charge of an electron to that of a positron is 1:1. Both the electron and positron have the same magnitude of charge but opposite in sign, with the electron being negative and the positron being positive.
an electron is about 1/1836 amu.
3 bondings + 1 electron pair = 4 (electron domains)
BrO3- is an ionic compound. It consists of the bromine ion (Br-) and the polyatomic ion bromate (BrO3-), which is a combination of covalent and ionic bonds.
Planar with an angle of 90 dergrees
No, BrO3- does not have a free radical. It is a stable ion with a formal charge of -1, consisting of a bromine atom bonded to three oxygen atoms.
PH3 has 3 bonding pairs and 1 non-bonding pair of electrons. Its electron pair geometry is Tetrahedral and its molecular geometry is Trigonal Pyramidal.
The ionic charge of bromate ion (BrO3-) is -1.
Anything with six electron groups, keep in mind an electron group is a bonded atom or an electron pair, is an octahedral. Anything in an octahedral and a lone pair is the square pyramidal geometry. So all angles between the atoms are a little less than 90 degrees and the angle of the electron pair is greater than 90.
The oxidation number for Br in BrO3 is +5. This is because the overall charge of the BrO3 molecule is -1, and the oxygen atoms have an oxidation number of -2 each. Therefore, the oxidation number of Br must be calculated as +5 to balance the charges.
The correct name for the BrO4^-1 ion is perbromate.
In the compound BrO3-, bromine is more electronegative than oxygen and has an oxidation number of +5 to satisfy the overall charge of the anion which is -1. Each oxygen atom has an oxidation number of -2, so the total oxidation numbers in BrO3- sum up to -1.
The hybridization of NiCl4 is sp3. Nickel (Ni) has 4 electron domains around it (1 for Ni and 3 for Cl atoms) which leads to the sp3 hybridization.
Remember, the geometry of a molecule has to do with how many electron pairs AND lone pairs there are around the CENTRAL atom. Basically, count up the lines and the pairs of dots. Notice that 'Xe' has 8 electrons in its valence shell, and 'F' has only 7. When we put 4 'F' atoms around 1 'Xe' atom, each Flourine atom is going to want to 'share' one of Xenon's electrons so that it can have 8 electrons. Also remember that when an atom shares electrons, it shares in pairs. Each shared bond has 2 electrons. Now count up the number of electron PAIRS around the CENTRAL atom. We have 4 bonds (one with each Fluorine atom), and 2 lone pairs of of electrons bringing our count up to 12 electrons around Xenon, or 6 pairs total. (This violates the 'Octet Rule', but it's ok in this situation) Here is a list of geometries according to the number of Electron Domains: 2 'ED's (electron domains) = Linear shape 3 'ED's = Trigonal Planar 4 'ED's = Tetrahedral 5 'ED's = Trigonal Bi-pyramid 6 'ED's = Octahedral The electron-domain geometry of XeF4 would be Octahedral. Hope this helped!