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What is the molar mass of MgS?
The molar mass of MgS (magnesium sulfide) is calculated by adding the atomic masses of magnesium (Mg) and sulfur (S). The atomic mass of Mg is approximately 24.31 g/mol, and S is approximately 32.06 g/mol. Therefore, the molar mass of MgS is approximately 24.31 + 32.06 = 56.37 g/mol.
How many moles is 1.346g of Mg?
To find the number of moles in 1.346g of Mg, you need to divide the mass by the molar mass of Mg (24.305 g/mol). 1.346g Mg / 24.305 g/mol = 0.055 moles Mg
What is the molar mass of MgH2?
The molar mass of MgH2 is calculated by adding the atomic masses of magnesium (Mg) and hydrogen (H). The atomic mass of Mg is approximately 24.31 g/mol, and the atomic mass of H is approximately 1.008 g/mol. Therefore, the molar mass of MgH2 is approximately 25.33 g/mol.
When 4.00g of magnesium burns the theoretical yield of magnesium oxide is?
2 Mg (s) + O2 (g) → 2 MgO (s)4.00mg x 1 mol Mg/24.305 x 2 mol MgO/2 mol Mg x 40.305g MgO/1 mol MgO==6.63g4.00g- Given24.305g- Atomic Mass of Magnesium40.305g- Atomic Mass of Magnesium Oxide
3 atoms of magnesium combine with 2 atoms of nitrogen.What will be the weight of magnesium which combines with 1.86g of nitrogen?
The molar mass of magnesium is 24.31 g/mol and the molar mass of nitrogen is 14.01 g/mol. So, 1.86g of nitrogen is equivalent to 0.133 mol. From the 3:2 ratio of magnesium to nitrogen, we find that 0.133 mol of nitrogen requires 0.1995 mol of magnesium. Therefore, the weight of magnesium combining with 1.86g of nitrogen is 4.85g.
