Magnesium has the molar mass of 24.305 grams per mole. 0.229 moles of Mg has a mass of about 5.57 grams.
The molar mass of MgS (magnesium sulfide) is calculated by adding the atomic masses of magnesium (Mg) and sulfur (S). The atomic mass of Mg is approximately 24.31 g/mol, and S is approximately 32.06 g/mol. Therefore, the molar mass of MgS is approximately 24.31 + 32.06 = 56.37 g/mol.
1.346 grams Mg (1 mole Mg/24.31 grams) = 0.05537 moles magnesium
The molar mass of MgH2 is calculated by adding the atomic masses of magnesium (Mg) and hydrogen (H). The atomic mass of Mg is approximately 24.31 g/mol, and the atomic mass of H is approximately 1.008 g/mol. Therefore, the molar mass of MgH2 is approximately 25.33 g/mol.
2 Mg (s) + O2 (g) → 2 MgO (s)4.00mg x 1 mol Mg/24.305 x 2 mol MgO/2 mol Mg x 40.305g MgO/1 mol MgO==6.63g4.00g- Given24.305g- Atomic Mass of Magnesium40.305g- Atomic Mass of Magnesium Oxide
Equation: 3Mg + N2 → Mg3N2 3mol Mg combines with 1mol N2. Molar mass N2 = 28.014g/mol 1.86g N2 = 1.86/28.014 = 0.0664mol N2 This will require 0.0664*3 = 0.1992mol Mg Molar mass Mg = 24.305g/mol 0.1992mol Mg = 24.305*0.1992 = 4.84g Mg required.
To solve this first the molar mass of Mg is needed (look at a periodic table). (Mg=23.0g/mol) Then convert the mols to grams as follows: (3.65 mol Mg) x (23.0 g/mol Mg) = 84.0 g Mg The mol units cancel in the conversion leaving only the gram units and the ammount in grams.
The molar mass of Mg O = 40.3044 g/mol
To calculate the mass of 5.1 x 10^20 molecules of ethanol, first determine the molar mass of ethanol (46.07 g/mol). Then convert this to mg/mol (46,070 mg/mol). Finally, multiply the molar mass by the number of molecules to find the total mass in mg (approximately 2.35 x 10^25 mg).
The molar mass of MgS (magnesium sulfide) is calculated by adding the atomic masses of magnesium (Mg) and sulfur (S). The atomic mass of Mg is approximately 24.31 g/mol, and S is approximately 32.06 g/mol. Therefore, the molar mass of MgS is approximately 24.31 + 32.06 = 56.37 g/mol.
The formula mass of magnesium nitrite octahydrate (Mg(NO2)2 * 8H2O) can be calculated by adding the atomic masses of all the elements in the compound. The atomic mass of Mg is 24.3 g/mol, N is 14.0 g/mol, O is 16.0 g/mol, and H is 1.0 g/mol. By adding these up, you get the formula mass of magnesium nitrite octahydrate.
1.346 grams Mg (1 mole Mg/24.31 grams) = 0.05537 moles magnesium
The molar mass of MgH2 is calculated by adding the atomic masses of magnesium (Mg) and hydrogen (H). The atomic mass of Mg is approximately 24.31 g/mol, and the atomic mass of H is approximately 1.008 g/mol. Therefore, the molar mass of MgH2 is approximately 25.33 g/mol.
The formula mass for MgCl2 (magnesium chloride) is calculated by adding the atomic masses of magnesium (Mg) and chlorine (Cl). The atomic mass of Mg is 24.31 g/mol and the atomic mass of Cl is 35.45 g/mol. Multiplying the atomic mass of Cl by 2 (since there are 2 chlorine atoms in MgCl2) and adding it to the atomic mass of Mg gives a formula mass of 95.21 g/mol for MgCl2.
2 Mg (s) + O2 (g) → 2 MgO (s)4.00mg x 1 mol Mg/24.305 x 2 mol MgO/2 mol Mg x 40.305g MgO/1 mol MgO==6.63g4.00g- Given24.305g- Atomic Mass of Magnesium40.305g- Atomic Mass of Magnesium Oxide
To find the percent composition of an element, you need to calculate the molar mass of the element in the compound and divide it by the molar mass of the whole compound, then multiply by 100. The molar mass of Mg(ClO4)2 is approximately 223.21 g/mol. The molar mass of chlorine in the compound is 70.906 g/mol. Therefore, the percent composition of chlorine in Mg(ClO4)2 is (70.906 g/mol / 223.21 g/mol) x 100 = 31.74%.
The formula mass of Mg(NO3)2, also known as magnesium nitrate, is 148.32 g/mol. This is calculated by adding the atomic masses of magnesium (24.31 g/mol), nitrogen (14.01 g/mol), and three oxygen atoms (16.00 g/mol each) together.
Equation: 3Mg + N2 → Mg3N2 3mol Mg combines with 1mol N2. Molar mass N2 = 28.014g/mol 1.86g N2 = 1.86/28.014 = 0.0664mol N2 This will require 0.0664*3 = 0.1992mol Mg Molar mass Mg = 24.305g/mol 0.1992mol Mg = 24.305*0.1992 = 4.84g Mg required.