What is the molarity of 67.94 mL aqueous solution containing 2.822 g of KI?

Answer 1

Molarity = moles of solute/Liters of solution.

get moles KI

2.822 grams KI (1 mole KI/166 grams)

= 0.017 moles KI ( 67.94 ml = 0.06794 Liters )

Molarity = 0.017 moles KI/0.06794 Liters

= 0.2502 M KI

Answer 2

To find the molarity, first calculate the number of moles of KI using its molar mass (166 g/mol). Then divide the moles of KI by the volume of the solution in liters (67.94 mL = 0.06794 L) to get the molarity. The molarity of the solution is approximately 6.24 M.