Molarity = number of moles / number of liters.
For this question the number of moles is 3 and the number of liters is 0.5
So 3/0.5 = 6
The solution is 6 M.
To determine the molarity, you need to know the volume of water the 3 moles of FeBr3 are dissolved in. With this information, you can use the formula: Molarity (M) = Moles of solute / Liters of solution. Therefore, if you dissolve 3 moles of FeBr3 in 1 liter of water, the molarity would be 3 M.
The molarity is 6 mol/l.
3 moles in 1 liter = 3 M
The molarity can be calculated using the formula: moles of solute divided by liters of solution. In this case, the moles of sucrose is 25, and the liters of solution is 50. This gives a molarity of 0.5 M.
To find the molarity of the solution, first, we need to determine the total volume of the solution in liters. Since the density of water is approximately 1 kg/L, 3 kg of water corresponds to about 3 liters. Molarity (M) is calculated as moles of solute divided by the volume of solution in liters. Thus, the molarity of the solution is ( \frac{6 \text{ moles}}{3 \text{ L}} = 2 \text{ M} ).
To determine the molarity, you need to know the volume of water the 3 moles of FeBr3 are dissolved in. With this information, you can use the formula: Molarity (M) = Moles of solute / Liters of solution. Therefore, if you dissolve 3 moles of FeBr3 in 1 liter of water, the molarity would be 3 M.
The molarity is 6 mol/l.
3 moles in 1 liter = 3 M
The molarity of a solution is calculated by dividing the number of moles of solute by the volume of the solution in liters. In this case, the molarity of the solution is 3 moles / 5 L = 0.6 M.
The molarity of the solution can be calculated by dividing the moles of solute by the volume of solution in liters. In this case, 2 moles of NaOH in 1620 mL (1.62 L) of water gives a molarity of approximately 1.23 M.
The molarity of the salt solution can be calculated by dividing the number of moles of solute (salt) by the volume of solution in liters. In this case, the molarity would be 10 moles / 20 liters = 0.5 moles per liter (M).
The molarity can be calculated using the formula: moles of solute divided by liters of solution. In this case, the moles of sucrose is 25, and the liters of solution is 50. This gives a molarity of 0.5 M.
6mol/2L
Molarity = moles of solute/Liters of solution Molarity = 6 Moles NaCl/2 Liters = 3 M NaCl ========
This molarity is 3 M.
Molarity is defined as moles solute/liter of solution6 moles/2 liters solution = 3 molar NOTE: This assumes no volume change and 2L is the final volume of solution.
Molarity = moles of solute/Liters of solutionSo, get moles HCl.73 grams HCl (1 mole HCl/36.458)= 2.00 moles HCl---------------------------Molarity = 2.00 moles HCl/2 Liters= 1 M HCl=======