Wiki User
∙ 10y agoMolarity is moles per litre. So here, you have to divide by 353ml, x 1000 (to get it per litre). .73/353*100 is 2.07 molar.
Wiki User
∙ 10y agoThe molarity of the solution is calculated by dividing the moles of solute by the volume of solution in liters. First, convert the volume from milliliters to liters (353 mL = 0.353 L). Then, divide the moles of NaOH (0.73 mol) by the volume of the solution in liters (0.353 L) to get the molarity. Molarity = 0.73 mol / 0.353 L ≈ 2.07 M.
It is 2.5 molar. The reason for this is that molarity means moles per litre. You have to multiply by 5 to get from 200ml to a litre, so you have to do the same with the moles.
The molarity can be calculated using the formula: moles of solute divided by liters of solution. In this case, the moles of sucrose is 25, and the liters of solution is 50. This gives a molarity of 0.5 M.
To determine the molarity, you need to know the volume of water the 3 moles of FeBr3 are dissolved in. With this information, you can use the formula: Molarity (M) = Moles of solute / Liters of solution. Therefore, if you dissolve 3 moles of FeBr3 in 1 liter of water, the molarity would be 3 M.
The molarity is 6 mol/l.
To find the molarity, first calculate the molar mass of glycerin to be 92.1 g/mol. Next, convert 1000g of water to liters by dividing by the density of water (1g/mL). Calculate the moles of glycerin in the solution. Finally, divide the moles of glycerin by the volume of the solution in liters to find the molarity.
It is 2.5 molar. The reason for this is that molarity means moles per litre. You have to multiply by 5 to get from 200ml to a litre, so you have to do the same with the moles.
The molarity of the solution can be calculated by dividing the moles of solute by the volume of solution in liters. In this case, 2 moles of NaOH in 1620 mL (1.62 L) of water gives a molarity of approximately 1.23 M.
The molarity of the salt solution can be calculated by dividing the number of moles of solute (salt) by the volume of solution in liters. In this case, the molarity would be 10 moles / 20 liters = 0.5 moles per liter (M).
The molarity of a solution is calculated by dividing the number of moles of solute by the volume of the solution in liters. In this case, the molarity of the solution is 3 moles / 5 L = 0.6 M.
The molarity can be calculated using the formula: moles of solute divided by liters of solution. In this case, the moles of sucrose is 25, and the liters of solution is 50. This gives a molarity of 0.5 M.
6mol/2L
The molarity of the solution is calculated by dividing the moles of solute by the liters of solution. In this case, the molarity would be 3 M (6 moles NaCl / 2 L solution = 3 M).
To determine the molarity, you need to know the volume of water the 3 moles of FeBr3 are dissolved in. With this information, you can use the formula: Molarity (M) = Moles of solute / Liters of solution. Therefore, if you dissolve 3 moles of FeBr3 in 1 liter of water, the molarity would be 3 M.
Molarity means moles in a litre. So here we divide by moles by 7.98 to get moles in a litre. This gives us 25.3133 molar. This figure is very high (likely to be over saturation level in water), so I'm not sure if your figures are correct.
This molarity is 3 M.
The molarity of a solution is calculated as moles of solute divided by liters of solution. In this case, 6 moles of NaCl dissolved in 2 L of water would give a molarity of 3 M (6 moles / 2 L).
The molarity of the solution can be calculated using the formula: Molarity = (moles of solute) / (volume of solution in liters). First, convert the mass of HCl to moles using its molar mass. Then, divide the moles by the volume of the solution in liters to find the molarity.