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Calculation in two steps:
- mass (g) / molar mass (g/mol) = moles NH4NO3
6.84 / (1*14.01 + 4*1.008 + 1*14.01 + 3*16.00) =
6.84 / (80.052) = 0.0854 mole NH4NO3
- NH4NO3 moles * 2 moles N/mole NH4NO3 = moles N atoms
0.00854*2 = 0.171 moles N atoms
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Does one mole of NH3 weigh more than one mole of H2O?
The mass of NH3 mole = its molecular weight = 14 + 3 x 1 = 17 The mass of H2O mole = its molecular weight = 2 x 1 + 16 = 18 This means that one mole of NH3 weigh less than one mole of H2O
How many grams of H2 are needed to produce 10.06 g of NH3?
The formula reaction for NH3 when using N2 and H2 is: (N2)+3(H2) ---> 2(NH3) Now, first step is to find the moles of the H2 reactant. This is found via (grams of reactant)/(molar mass of reactant). There are 10 grams, and the molar mass of H2 is approximately 2.016. Therefore, the equation should look like: 10/2.016. This yields a value of ~4.9606 moles of H2. Now, you use the molar ratio from the reactant to the product to determine how many moles of product were yielded. According to the reaction, three moles of H2 are required to produces 2 moles of NH3. So, the mole ratio is 2/3. Multiply the number of moles of H2 with the molar ratio to determine the moles of NH3. 4.0606 * 2/3 = 3.3071 moles of NH3. Multiply the number of moles with the molar mass of NH3 (17.0306), and voila! 3.3071 * 17.0306 = 56.3216 grams. Now, if your teacher is feeling like a stickler about significant figures, than that value should be rounded to 56 grams of NH3.
How does the experimental mole ratio compare with the theoretical mole ratio?
The experimental mole ratio is obtained from actual experimental data, while the theoretical mole ratio is calculated based on the balanced chemical equation. Comparing the two can reveal discrepancies and provide insight into the accuracy of the experimental results or any potential sources of error in the experiment.
How many moles of nh3 are produced from 1.5 moles h2?
The balanced chemical equation for the reaction is: 3H2 + N2 -> 2NH3 From the stoichiometry of the balanced equation, 3 moles of H2 produces 2 moles of NH3. Therefore, if you have 1.5 moles of H2, you will produce 1.5 moles * (2 moles NH3 / 3 moles H2) = 1 mole of NH3.
What mass of NH3 is produced when 1.20 mol of N2 react completely in the following equation N2 plus 3H2 2NH3?
N2 + 3H2 ==> 2NH3moles N2 = 1.20 molesmoles NH3 formed = 1.20 moles N2 x 2 moles NH3/1 moles N2 = 2.40 moles NH3mass NH3 = 2.40 moles x 17 g/mole = 40.8 g NH3
How many moles of nitrate oxide can be made from the reaction of 3.80 mole NH3 with 5.15 mole o2?
You can use the balanced chemical equation to determine the number of moles of nitric oxide formed. The balanced equation is 4NH3 + 5O2 → 4NO + 6H2O, indicating a 1:1 mole ratio between NH3 and NO. As only NH3 is limiting in this case, 3.80 moles of NH3 will produce 3.80 moles of NO.
What is the mole ratio of nitrogen to ammonia in the equation 1N2 3H2 equals NH3?
The mole ratio of nitrogen to ammonia in the equation is 1:2. This means that for every 1 mole of nitrogen (N2) that reacts, 2 moles of ammonia (NH3) are produced.
How many molecules (not moles) of NH3 are produced from 5.69104 g of H2?
First, calculate the number of moles of H2 using its molar mass of 2 g/mol. Then, use the balanced chemical equation for the reaction between H2 and NH3 to determine the mole ratio. Finally, convert the moles of H2 to moles of NH3 using the mole ratio and then calculate the number of molecules of NH3 produced.
How much does a mole of nh3 weigh?
The molar mass of NH3 is 17.03 grams per mole. Therefore, a mole of NH3 weighs 17.03 grams.
Number ammonia molecules in 3.75g of CH4?
To find the number of ammonia molecules in 3.75g of CH4, you first need to convert 3.75g of CH4 to moles using the molar mass. Then, you need to use the mole ratio between CH4 and NH3 to find the number of ammonia molecules in the given amount of CH4. The mole ratio for CH4 to NH3 is 1:3, as 1 molecule of CH4 produces 3 molecules of NH3 in the balanced chemical equation.
How many moles of N2 reacted if 0.40 mole NH3 is produced?
For the reaction N2 + 3H2 -> 2NH3, the mole ratio between N2 and NH3 is 1:2. Therefore, if 0.40 mole of NH3 is produced, 0.20 moles of N2 reacted.
Does one mole of NH3 weigh more than one mole of H2O?
The mass of NH3 mole = its molecular weight = 14 + 3 x 1 = 17 The mass of H2O mole = its molecular weight = 2 x 1 + 16 = 18 This means that one mole of NH3 weigh less than one mole of H2O
How does the experimental mole ratio compare with the theoretical mole ratio?
The experimental mole ratio is obtained from actual experimental data, while the theoretical mole ratio is calculated based on the balanced chemical equation. Comparing the two can reveal discrepancies and provide insight into the accuracy of the experimental results or any potential sources of error in the experiment.
Find out the mass of HCL needed to react completely with 0.20 g of ammonia gass?
To find the mass of HCl needed to react completely with 0.20 g of ammonia gas, you need to use the stoichiometry of the balanced chemical equation of the reaction between HCl and ammonia. From the balanced equation, determine the mole ratio between HCl and ammonia. Then use this ratio to calculate the mass of HCl required to react completely with 0.20 g of ammonia gas.
How many grams of NH3 can be produced from 12.11 g H2?
N2(g) + 3H2-> 2NH3(g) This is the balanced equation Note the mole ratio between N2, H2 and NH3. It is 1 : 3 : 2 This will be important. moles N2 present = 28.0 g N2 x 1 mole N2/28 g = 1 mole N2 present moles H2 present = 25.0 g H2 x 1 mole H2/2 g = 12.5 moles H2 present Based on mole ratio, N2 is limiting in this situation because there is more than enough H2 but not enough N2. moles NH3 that can be produced = 1 mole N2 x 2 moles NH3/mole N2 = 2 moles NH3 can be produced grams of NH3 that can be produced = 2 moles NH3 x 17 g/mole = 34 grams of NH3 can be produced NOTE: The key to this problem is recognizing that N2 is limiting, and therefore limits how much NH3 can be produced.
What is mass of ammonia?
The molar mass of ammonia (NH3) is approximately 17.03 grams per mole.
What is the mole to mole ratio of nitrogen gas and hydrogen gas?
The mole-to-mole ratio of nitrogen gas (N2) to hydrogen gas (H2) is 1:3. This means that in a balanced chemical equation, one mole of N2 reacts with three moles of H2 to form two moles of ammonia (NH3) in the Haber process.
