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XeO4 is tetrahedral. The total number of valence electrons in the molecule is 32 (6 x 4 oxygens and 8 from the Xe) which when divided equally among the oxygens with a double bond to the Xe gives every O molecule a full outer shell, and the Xe an extended shell. If XeO4 (4-), then each O would be single-bonded to the Xe.
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