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This link tells you the answers to the questions, but have no clue about the working - will update later! http://answers.Yahoo.com/question/index?qid=20070410010133AA3Y2o6

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To calculate the percent by mass of each compound, you need to know their molar masses. For CuSO4•5H2O (copper(II) sulfate pentahydrate), the molar mass is 249.68 g/mol. For MgSO4•7H2O (magnesium sulfate heptahydrate), the molar mass is 246.47 g/mol. Now, divide the molar mass of each compound by the sum of the molar masses of both compounds and multiply by 100 to get the percent by mass. This will give the percentage composition of each compound within the mixture.

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11mo ago
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Q: What is the percent by mass of cuso4 5h2o mgso4 7h2o?
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