What is the percent composition of carbon in the compound sucrose?

Answer 1

Sucrose: C12H22O11

Formula Weight: 342.3

Carbon: 12 * 12.01 g/mol = 144.12

144.12/342.3 = 42.10% Carbon

You can always check the other elements to double check:

Hydrogen: 22*1 = 22

22/342.3 = 6.4% Hydrogen

Oxygen: 11*16.01 = 176.11

176.11/342.3 = 51.44% Oxygen

Answer 2

Sucrose has a chemical formula of C12H22O11. To calculate the percent composition of carbon, determine the molar mass of carbon in sucrose: 12 (number of carbon atoms) x 12.01 g/mol (molar mass of carbon) divided by the molar mass of sucrose (342.3 g/mol) x 100. The percent composition of carbon in sucrose is approximately 42.11%.

Answer 3

-first calculate the relative molecular mass (RMM) of glucose

12(6)+1(12)+16(6)= 180

-then the RMM of 6 molecules of carbon

12x6=72

- calculate the percentage

72/180= 0.4 and multiply by 100 to get 40%

Answer 4

Glucose has a molar mass of 180g/mol, and we arrive at this figure by adding up the atomic masses of all its constituent atoms. Carbon accounts for 72 of these 180g (12x6), so 72/180 = 0.4, which is 40%.

Answer 5

Glucose is a simple sugar with the chemical formula of C6H12O6. Its percent composition is carbon = 40.0 percent, hydrogen = 6.7 percent and oxygen = 53.3 percent.