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Prob = (8.5 - 7.4)/(8.5 - 6.8) = 1.1/1.7 = 0.6471

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13y ago
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4w ago

The probability can be calculated by finding the proportion of the interval where the diameter is greater than 7.4 mm. In this case, the proportion of the interval greater than 7.4 mm is (8.5 - 7.4) / (8.5 - 6.8) = 0.55, so the probability is 55%.

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Q: What is the probability that a randomly selected ball bearing has a diameter greater than 7.4 millimeters provided that the uniform distribution over the interval is 6.8 to 8.5 millimeters.?
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