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What is the resultant velocity of the plane if an airplane flying toward 0 degree at 90.0 km per hour is being blown toward 90 degrees at 50.0 km per hour?
Wiki User
β 16y ago
This problem can be solved using the pythagorean theorem
A2 + B2 = C2
A = 90 km/h
B = 50 km/h 902 + 502 = 10,600
√10,600 = 103.0
C = 103 km/h
Wiki User
β 16y ago
The resultant velocity can be found using vector addition. The component of velocity in the x-direction is 90 km/h, and in the y-direction is 50 km/h. Using the Pythagorean theorem, the resultant velocity magnitude is β(90^2 + 50^2) km/h = β(8100 + 2500) = β10600 β 103 km/h. The direction of the resultant velocity can be found using trigonometry: tanΞΈ = (50 / 90), so ΞΈ β 30.96 degrees. So, the resultant velocity of the airplane is approximately 103 km/h at an angle of 30.96 degrees from the original direction.
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