In case of 1s order Splitting above answer is correct. in case of Non-1st Order splitting we should follow the following example
let for AMX(Quartet)
take our hand fingers for spectrum explanation(vomit thumb finger), distance between little finger to middle finger let it 'X' minus distance between showing finger and side finger of little finger let it 'y'.
Now the coupling constant is (X-Y)/2.
Kindly suggest if any mistake or difficulty to understand.
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In NMR spectroscopy, a coupling constant is a measure of the interaction between different nuclear spins in a molecule. It provides information about the connectivity and relative arrangement of atoms in a molecule. The value of the coupling constant is influenced by the number of bonds and the dihedral angle between the coupled nuclei.
No, it is not true.
Yes this is true
Kinematics does not require constant acceleration. There are different equations for different situations. So some of the equations will be valid even when the acceleration is not constant.
It is something that is proven as true and indisputable.
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