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What is the wavelength of a photon emitted during a transition from ni 6 to nf 3 state in the H atom?
Wiki User
ā 15y ago
if you know the Rydberg constant this is fairly simple question.
the Rydberg constant is 1.097x107m-1 The equation for is
1 / lambda = 1.097x107m-1 ((1/62) - (1/32))
Then the rest is peanuts.
Wiki User
ā 15y ago
The energy difference between the initial and final states can be calculated using the Rydberg formula. Once the energy is known, you can use the relationship E = hc/Ī», where E is the energy, h is Planck's constant, c is the speed of light, and Ī» is the wavelength of the photon. Solving for Ī» will give you the wavelength of the photon emitted during the transition.
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Transition A produces light with a wavelength of 400 nm Transition B involves twice as much energy as A What wavelenth light does it produce?
Transition B produces light with half the wavelength of Transition A, so the wavelength is 200 nm. This is due to the inverse relationship between energy and wavelength in the electromagnetic spectrum.
What is the wavelength of the photon emitted when a hydrogen atom goes from the second energy level to the first energy level?
The wavelength of the photon emitted can be calculated using the Rydberg formula: 1/wavelength = R(1/n1^2 - 1/n2^2), where R is the Rydberg constant, n1 is the initial energy level (2 in this case), and n2 is the final energy level (1 in this case). Plugging in the values gives the wavelength of the photon emitted.
What is the energy of a photon emitted with wavelength of 518 nm?
3.84 x 10-19 joules.
What effect would lower wavelength have on the emitted photoelectrons?
Lowering the wavelength of incident light increases its energy, which in turn can increase the kinetic energy of the emitted photoelectrons. This is in line with the photon energy equation E=hf, where E is energy, h is Planck's constant, and f is frequency (which is inversely proportional to wavelength).
What is the process in which an electron returns to a lower energy level and emits a photon?
This process is called "emission." When an electron transitions from a higher to a lower energy level within an atom, it releases a photon of light corresponding to the energy difference between the two levels. This emitted photon carries away the energy that the electron lost during the transition.
What is the source of an emitted photon?
An emitted photon is typically generated when an electron transitions from a higher energy level to a lower energy level within an atom or molecule. This transition releases energy in the form of a photon.
When an electron in atom changes energy states a photon is emitted If the photon has a wavelength of 550 nm how did the energy of the electron change?
The energy of the electron decreased as it moved to a lower energy state, emitting a photon with a wavelength of 550 nm. This decrease in energy corresponds to the difference in energy levels between the initial and final states of the electron transition. The energy of the photon is inversely proportional to its wavelength, so a longer wavelength photon corresponds to lower energy.
Transition A produces light with a wavelength of 400 nm Transition B involves twice as much energy as A What wavelenth light does it produce?
Transition B produces light with half the wavelength of Transition A, so the wavelength is 200 nm. This is due to the inverse relationship between energy and wavelength in the electromagnetic spectrum.
What is the wavelength of the photon emitted when a hydrogen atom goes from the second energy level to the first energy level?
The wavelength of the photon emitted can be calculated using the Rydberg formula: 1/wavelength = R(1/n1^2 - 1/n2^2), where R is the Rydberg constant, n1 is the initial energy level (2 in this case), and n2 is the final energy level (1 in this case). Plugging in the values gives the wavelength of the photon emitted.
What is the energy of a photon emitted with wavelength of 518 nm?
3.84 x 10-19 joules.
What is the energy of a photon emitted with a wavelength of 518 mp?
The energy of a photon can be calculated using the equation E = hc/Ī», where h is Planck's constant, c is the speed of light, and Ī» is the wavelength. Plugging in the values, the energy of a photon with a wavelength of 518 nm is approximately 3.82 eV.
What state does an electron move to its ground state from in a gaseous atom in order for a photon to be emitted?
The electron moves from an excited state to the ground state in a gaseous atom in order for a photon to be emitted. When the electron drops to a lower energy level, it releases energy in the form of a photon with a specific wavelength characteristic of the transition.
Why is a shorter wavelength of light emitted when an electron falls from n4 to n1 than when an electron falls from n2 to n1?
When an electron falls from n4 to n1, it releases more energy because it is transitioning between high energy states. This higher energy transition corresponds to a shorter wavelength of light being emitted, according to the energy of the photon being inversely proportional to its wavelength. In contrast, when an electron falls from n2 to n1, the energy released is less, resulting in a longer wavelength of light emitted.
How does photon energy change with wavelength?
The energy of a photon is inversely proportional to its wavelength. This means that as the wavelength increases, the energy of the photon decreases. Conversely, as the wavelength decreases, the energy of the photon increases.
What wavelength is a transition from n5 to n3?
The wavelength of a transition from n=5 to n=3 in hydrogen-like atoms can be calculated using the Rydberg formula: 1/Ī» = R(1/nāĀ² - 1/nāĀ²), where R is the Rydberg constant. The transition will result in the emission of a photon with a wavelength in the ultraviolet region.
What is the wavelength of a photon whose energy is twice that of a photon with a 580 nm wavelength?
Since the energy of a photon is inversely proportional to its wavelength, for a photon with double the energy of a 580 nm photon, its wavelength would be half that of the 580 nm photon. Therefore, the wavelength of the photon with twice the energy would be 290 nm.
What occurs as the wavelength of a photon increases?
As the wavelength of a photon increases, its frequency decreases. This means the energy of the photon decreases as well, since photon energy is inversely proportional to its wavelength.
