The density of Mercury (Hg) is 13.6 g/mL. Therefore, the mass of Hg that will occupy a volume of 50.0 mL can be calculated using the formula: mass = volume x density. Substituting the values, we get mass = 50.0 mL x 13.6 g/mL = 680 grams.
The volume is 0,046 L.
To solve, use the combined gas law: (P1V1/T1) = (P2V2/T2). Plug in the initial conditions (P1 = 420 mm Hg, V1 = 500 mL, T1 = 20°C), and the final conditions (P2 = 650 mm Hg, T2 = 80°C) to find V2, the final volume. Remember to convert temperatures to Kelvin by adding 273 to the Celsius temperature.
The atomic mass of mercury (Hg) is 200.59 grams per mole.
The atomic mass of mercury (Hg) is approximately 200.59 grams per mole.
500 mmHg or 500 torr is a gas pressure approximately 66% of the standard sea level air pressure of 760 torr ... it is the air pressure one would find at an altitude of approximately 3km or 10000 feet ... at sea level, 500 torr would be considered a partial vacuum of 0.66 atm.
The volume is 0,046 L.
0.05 L
1 gram = 1 mL so;500 g = 500 mL34
To solve, use the combined gas law: (P1V1/T1) = (P2V2/T2). Plug in the initial conditions (P1 = 420 mm Hg, V1 = 500 mL, T1 = 20°C), and the final conditions (P2 = 650 mm Hg, T2 = 80°C) to find V2, the final volume. Remember to convert temperatures to Kelvin by adding 273 to the Celsius temperature.
To find the volume of the dry gas at standard conditions (0°C and 1 atm), we need to correct for the water vapor using the vapor pressure of water at 20°C. The vapor pressure of water at 20°C is 17.5 mm Hg. Therefore, the pressure of the dry gas is 622.0 mm Hg (total pressure) - 17.5 mm Hg (water vapor pressure) = 604.5 mm Hg. Using the ideal gas law, we can calculate the volume of the dry gas at standard conditions.
500
The atomic mass of mercury (Hg) is 200.59 grams per mole.
The atomic mass of mercury (Hg) is approximately 200.59 grams per mole.
To find the new pressure after the compression, you can use Boyle's Law, which states that pressure and volume are inversely related at constant temperature. Using the formula P1V1 = P2V2, where P1 = 760 mm Hg, V1 = 500 ml, V2 = 100 ml, you can calculate the new pressure (P2) by rearranging the formula as follows: P2 = P1V1 / V2 = (760 mm Hg * 500 ml) / 100 ml. Substituting these values gives you the new pressure after compression.
To find the percent composition of mercury (Hg) in the compound, you first calculate the molar mass of each element. Then, find the molar mass of the compound by adding the molar masses of Hg and Br. Divide the molar mass of Hg by the molar mass of the compound and multiply by 100 to get the percentage. In this case, the percent composition of Hg in the compound is approximately 71%.
At standard temperature and pressure. This means that, more or less, there are 6.022 X 10^23 diatomic molecules of H2 in that much volume. ( the volume not being under more than standard pressure; 760mm/Hg ) In twice the volume about twice the molecules under STP.
Mercury (Hg) has an atomic mass of 200.59