For a tungsten filament lamp rated at 300 Watts on 120V, the current can be calculated using the formula: Power = Voltage x Current. Thus, Current = Power / Voltage = 300W / 120V = 2.5A. To control five 300W tungsten filament lamps, you'd need a switch rated for at least 2.5A at 120V, preferably with a safety margin for additional load or inrush current. A switch with a rating of 10A at 120V would provide a suitable capacity for this circuit.
For a tungsten filament lamp rated at 300 Watts on 120V, the current can be calculated using the formula: Power = Voltage x Current. Thus, Current = Power / Voltage = 300W / 120V = 2.5A. To control five 300W tungsten filament lamps, you'd need a switch rated for at least 2.5A at 120V, preferably with a safety margin for additional load or inrush current. A switch with a rating of 10A at 120V would provide a suitable capacity for this circuit.
Watts = Volts x Current
5 x 300 = 1500 = 120 x Amps
Amps = 1500 / 120 = 12.5 amps
Just install a standard wall switch rated at least 15 amps at 120 VAC. All lights are in parallel and fed from a single switch.
Watts = Volts x Current
5 x 300 = 1500 = 120 x Amps
Amps = 1500 / 120 = 12.5 amps
Just install a standard wall switch rated at least 15 amps at 120 VAC. All lights are in parallel and fed from a single switch.
Your load current will be A = W/E, Amps = 1500/120 = 12.5 amps. This is just a bit over the allowed 80% continuous loading rating. The circuit should be fed with a 20 amp breaker with a feeder of #12 wire. The switch should be a single pole single throw rated at 20 amps for optimal operation. With this rating no heating of the switch should occur.
1500 watts on 120 v is a 13 amp load. To prevent excessive inrush currents, the lights should grouped and fed through two or three separate switches operated in sequence.
Total wattage and amperage are 300 x 5 = 1500 watts/120 volts = 12.5 amps. A single pole single throw 20 amp rated switch will work in this situation.
Because the filament is in effect a resistor. Copper is too good a conductor to provide resistance to the current, and would simply allow the current to complete the circuit. The light is generated by the filament glowing as it heats up in resistance to the current. Tungsten is a much better resistor.
No. The filament completes the circuit, so if the filament is blown the circuit is incomplete, so no electricity flows.
No, the bulb will not light if the filament is broken because the filament is the part of the bulb that creates light when electricity passes through it. Without a functioning filament, there is no source of light in the bulb.
A light bulb filament acts as a resistor because it is made of a material with high resistivity, such as tungsten. When an electric current passes through the filament, the atoms in the material resist the flow of electrons, converting electrical energy into heat and light. This resistance causes the filament to heat up and emit light.
A light bulb typically consists of a filament, which produces the light when electricity passes through it, and a glass bulb enclosing the filament to protect it from damage and to contain the inert gas (such as argon or nitrogen) that helps prevent the filament from burning. The bulb also has a base that connects the light bulb to the electrical circuit.
The incandescent light bulb uses a filament made of tungsten to produce light when electricity passes through it.
Light bulbs typically contain a filament (often made of tungsten), a glass enclosure, and an inert gas like argon or nitrogen to prevent the filament from burning out too quickly. They also have a base to connect to the electrical circuit.
When the filament in a light bulb is broken, it creates an open circuit, which interrupts the flow of electricity. Without a complete circuit, the electricity cannot pass through the filament to produce light. As a result, the light bulb does not illuminate.
A bulb does not light up if there is no voltage available across the bulb, or if the bulb is burned out.
When a flash light is switched on the circuit between the lamp and the batteries is complete. When the circuit is complete, the electrons flow from the positive terminal of the batteries through the tungsten filament back to the negative terminal of the batteries. Once the electricity flows through the filament it starts glowing producing a bright light. When the the torch light is switched off the circuit is broken and the flow of electricity is disrupted switching off the light.
no, the circuit won't complete
As an incandescent light bulb is used, tungsten slowly evaporates from the filament causing it to get thinner. When it gets too thin it can no longer carry the current and part of it melts causing the bulb to blow out.
Because the filament is in effect a resistor. Copper is too good a conductor to provide resistance to the current, and would simply allow the current to complete the circuit. The light is generated by the filament glowing as it heats up in resistance to the current. Tungsten is a much better resistor.
A filament lamp produces light by converting electrical energy into heat and then light. It acts as a resistive load in the circuit, meaning it resists the flow of current and causes the filament to glow and produce light.
No. The filament completes the circuit, so if the filament is blown the circuit is incomplete, so no electricity flows.
No, the bulb will not light if the filament is broken because the filament is the part of the bulb that creates light when electricity passes through it. Without a functioning filament, there is no source of light in the bulb.
Using a thick tungsten wire in an electric bulb would increase the resistance of the wire, which would result in more heat being produced when current flows through it. This increased heat would cause the tungsten wire to glow brighter and produce more light.