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-- You haven't said what the object's speed was at the beginning of the

25 minutes. We'll assume that it started from rest at the beginning of

this whole exercise.

-- We're also going to work exclusively with the object's speed. Since you

haven't said anything about the direction in which it moves at any moment,

we have no way to work with velocity. Fortunately, it doesn't matter.

The motion occurs in three distinct periods, which we'll consider separately:

Period I:

Zero to 90 m/s in 25 minutes.

Average speed = 45 m/s.

Distance = (average speed) x (time) = (45 meter/sec) x (60 sec/min) x (25 min) = 67,500 meters.

Period II:

(90 meters/sec) x (3,600 sec/hour) x (2 hours) = 648,000 meters

Period III:

A perfect time-reversal of Period-I ... like running the video backwards.

Same distance as Period-I = 67,500 meters.

Total distance = (67,500) + (648,000) + (67,500) = 783 kilometers.

======================================================

Period-I

S = vit + 1/2 a t2

vi = 0

Acceleration = [ (90 meter/sec) x (1/25 min) ] x (1 min/60 sec) = 0.06 meter/sec2

t = 25 minutes = 1,500 sec

1/2 a t2 = 1/2 (0.06) (1,500)2 = 67,500 m

Period-II

S = v t = (90 meters/sec) x (2 hours) x (3,600 sec/hour) = 648,000 m

Period-III

Either recognize that Period-III is exactly the same as Period-I in reverse,

or else

you can use

S = vit + 1/2 a t2

vi = 90 meters/sec

t = 25 min = 1,500 sec

Acceleration = -0.06 meter/sec2

vit + 1/2 a t2 = (90)(1,500) + 1/2(-0.06)(1,500)2 = (135,000) + (-67,500) = 67,500 m

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Stopping a vehicle with good brakes from 20 miles per hour under good conditions required about?

Stopping a vehicle with good brakes from 20 miles per hour under good conditions typically requires a distance of about 20 to 30 feet. This distance can vary based on factors such as the type of brakes, tire condition, and road surface. Generally, the stopping distance includes the reaction time of the driver and the braking distance itself.


If only external force can change the velocity of a body how can the internal force of the brakes bring a car to rest?

It is not the force of the brakes that is stopping the car but rather external force of friction between tires and the road. Notice that no matter what the force at the brakes is, the car won't stop if there is no friction there(ie. the road is slippery). This is an excellent question. Consider the NASA space shuttle. It has brakes, yet the brakes work only on the ground - only while the shuttle is landing. Why? In space, the brakes have nothing to react against. So, as the questioner suspects, the internal forces of the brakes alone are not sufficient to change the velocity of the space shuttle. But once the shuttle lands, and is rolling down the runway, applying the brakes creates friction between the wheels and the runway. And it is the external force of the runway pushing back against the braking wheels that causes the shuttle to slow down.


What is the best way to stop with ABS brakes on ice and snow?

To stop with ABS brakes on ice and snow, apply steady pressure to the brake pedal. Do not pump the brakes, as ABS brakes are designed to prevent wheel lock-up. Maintain a safe following distance and make smooth steering inputs to help maintain control while braking.


This is the distance your vehicle travels from the moment you first see a hazard to the moment you come to a full stop?

That distance is known as the total stopping distance, which consists of both the thinking distance (distance traveled while recognizing a hazard and reacting) and the braking distance (distance traveled from applying the brakes to coming to a complete stop). The total stopping distance can vary depending on factors such as speed, road conditions, and vehicle condition.


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Related Questions

What the total distance of a body acquires the velocity of 90 km per hour in 25 minutes it then continuous for 2 hours when brakes applied it comes into rest in 25 minutes?

255 km


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If you find skid marks 180 meters long and assuming the deceleration was 10 minutes how fast was the car traveling before it hit the brakes?

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What is braking distance?

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What is an element of total stopping distance?

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