The half-life of 27Co60 is about 5.27 years. 15.8 years is 3 half-lives, so 0.53 or 0.125 of the original sample of 16 g will remain, that being 2 g.
5g would remain
I suppose that you think to the radioactive isotope Cs-17; After 4 years remain 9,122 g.
This time is 17 190 years.
2 1/2 g
2 1/2 g
In theory, they can remain unchanged for their entire existence. However, in practise, nature isn't so nice and evolution happens eventually.
5g would remain
Approximately 400 grams of the potassium-40 sample will remain after 3.91 years, as potassium-40 has a half-life of around 1.25 billion years. This means that half of the initial sample would have decayed by that time.
The answer depends on 3240 WHAT: seconds, days, years?
I suppose that you think to the radioactive isotope Cs-17; After 4 years remain 9,122 g.
This time is 17 190 years.
The president can remain in office for 2 four year terms . A total of eight years maximum
25/100 = 1/4 of the original sample. The "half-life" must pass twice, yielding (1/2) x (1/2) = 1/4 of the original sample. The half-life of Carbon-14 is listed as ( 5,730 ± 40 ) years. Twice that is ( 11,460 ± 80 ) years
In warm wet conditions leather will decompose in several years. In dry conditions leather will remain unchanged for hundreds of years.
10 grams... If the half-life is 100 years, that means after 100 years, half the original mass remains. After another 100 years, the mass is halved again. 40/2=20... 20/2=10.
After 6 years, approximately 5 grams of cesium-137 would remain from a 10 g sample due to its half-life of around 30 years. This decay is exponential, with about half of the original sample decaying every 30 years.
Plutonium-239 has a half-life of about 24,100 years, meaning it takes that long for half of a sample to decay. In 43 years, which is much shorter than the half-life, only a tiny fraction of the plutonium would decay. Therefore, after 43 years, approximately 99.83 grams of the original 100-gram sample would remain.