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What volume of 0305 M AgNO3 is required to react exactly with 155.0ml of 0274 M Na2SO4 solution?
Wiki User
∙ 12y ago
155.0 mL x 0.274 M SO42- reacts with 155.0 x 0.274 * 2 (Ag+/SO42-) = 84.94 mmol Ag+
84.94 mmol Ag+ is in 84.94 (mmolAg+) / 0.305 (M Ag+) = 84.94/0.305 = 278.5 mL of 0.305 M Ag+.
Na+ and NO3- are tribuned out of this reaction.
Wiki User
∙ 12y ago
To solve this, we can use the concept of stoichiometry. First, we need to write the balanced chemical equation for the reaction between AgNO3 and Na2SO4 to determine the mole ratio between them. Then, we can use the mole ratio to calculate the moles of AgNO3 needed to react with the given moles of Na2SO4. Finally, we can convert the moles of AgNO3 to volume using its molarity.
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What is the concentration of Na2SO4 solution prepared by dissolving 5.35 g of Na2SO4 in sufficient water to give 330 ml of solution?
First.Get moles sodium sulfate.5.35 grams Na2SO4 (1 mole Na2SO4/142.05 grams)= 0.0377 moles Na2SO4-------------------------------------Second.Molarity = moles of solute/Liters of solution ( 330 mL = 0.33 Liters )Molarity = 0.0377 moles Na2SO4/0.33 Liters= 0.114 M Na2SO4=============
Is Na2So4 abasic solution?
No, Na2SO4 does not affect the pH of a solution. It is a neutral salt because it is derived from a strong base (NaOH) and a strong acid (H2SO4).
How many liters of a 0.250 M BaCl2 solution are needed to react with 0.0325 L of a 0.160 M Na2SO4 solution?
The answer is 20,79 mL (0,021 L).
What volume (in mL) of 0.25M NaSO4 solution is needed to precipitate all the barium as BaSO4(s) from 12.5mL of 0.15M Ba(NO3)2 solution?
The chemical equation is:Ba(NO3)2 + Na2SO4 = BaSO4 + 2 NaNO3The volume (in mL) of 0,25M Na2SO4 solution needed to precipitate all the barium as BaSO4(s) from 12,5mL of 0,15M Ba(NO3)2 solution is 7,5 mL.
What are the spectator ions in Bal2 plus Na2SO4?
The spectator ions in the reaction between BaCl2 and Na2SO4 are Na+ and Cl-. These ions do not participate in the reaction and remain in the solution unchanged.
What is the concentration of Na2SO4 solution prepared by dissolving 5.35 g of Na2SO4 in sufficient water to give 330 ml of solution?
First.Get moles sodium sulfate.5.35 grams Na2SO4 (1 mole Na2SO4/142.05 grams)= 0.0377 moles Na2SO4-------------------------------------Second.Molarity = moles of solute/Liters of solution ( 330 mL = 0.33 Liters )Molarity = 0.0377 moles Na2SO4/0.33 Liters= 0.114 M Na2SO4=============
What is the molality of a solution containing 10.0g of Na2SO4 dissolved in 1000.0g of water?
To find the molality, we first calculate the moles of Na2SO4: 10.0g Na2SO4 * (1 mol Na2SO4 / 142.04g Na2SO4) = 0.0705 moles Na2SO4. Then, molality is calculated as moles of solute (Na2SO4) / kilograms of solvent (water): 0.0705 mol / 1.000 kg = 0.0705 mol/kg, which is the molality of the solution.
What is the pH of 0.25M Na2SO4?
The pH of a solution of Na2SO4 at a concentration of 0.25M is about 7, which is neutral. Na2SO4 is a salt formed from a strong base (NaOH) and a strong acid (H2SO4), so it does not significantly affect the pH of the solution.
What is the pH of Na2SO4?
The pH of a solution of Na2SO4 would be around 7, which is considered neutral. This is because Na2SO4 is a salt that dissociates completely in water to form Na+ and SO4 2- ions, which do not have a significant effect on the pH of the solution.
Will Na2SO4 and benzene form a solution?
No, sodium sulfate (Na2SO4) is not soluble in benzene because it is a polar compound and benzene is a nonpolar solvent. Therefore, they will not form a homogeneous solution.
What is the chemical equation of aqueous solution of sodium sulphite?
As sodium sulfite (Na2SO4) dissolves, it dissociates into its ions: Na2SO4 --> 2Na+ + SO32-
How many sodium ions are present in 325 mL of 0.850 M Na2SO4?
There are 0.850 moles of Na2SO4 in 325 mL of 0.850 M solution. Since Na2SO4 contains 2 sodium ions per formula unit, there will be 2*0.850 moles of sodium ions in the solution. Thus, there are 1.7 moles of sodium ions in 325 mL of 0.850 M Na2SO4 solution.
What is the balanced equation for a reaction between sodium sulfate solution and calcium chloride solution?
The balanced chemical equation for the reaction between sodium sulfate solution and calcium chloride solution is: Na2SO4 (aq) + CaCl2 (aq) -> 2NaCl (aq) + CaSO4 (s)
What is the solubility of BaSO4 in a 0.15 M solution of Na2SO4?
BaSO4 is insoluble in water, even in the presence of Na2SO4. This is due to the low solubility product constant of BaSO4, meaning it will not dissolve in a 0.15 M solution of Na2SO4.
What is the effect of heating the solution on the particale size of NA2SO4 preciptat?
Seltzer is a solution of a gas(carbon dioxide) and water
What is the boiling point of a 2.35 m solution of sodium sulfate Na2SO4?
103.6ºC
Is naso4 soluble or insoluble?
Sodium sulfate (Na2SO4) is soluble in water. It dissolves to form a clear, colorless solution.
