The volume of carbon dioxide is 8,4 L at oC.
It is CaCO3.....it is the same as marbleFormula: CaCO3
caco3 is solid form. its density is high so caco3 is not soluble in water. but co2 mix in water befuor the mix in caco3 . so caco3 is soluble after mixing the co2 .
CaCO3 + 2HCl --> CaCl2 + H2O + CO2
There are 2 oxygen atoms in one molecule of CaCO3. To calculate the number of oxygen atoms in 50 grams of CaCO3, you first need to find the number of moles of CaCO3 using its molar mass. Then, multiply the number of moles by the number of atoms of oxygen per molecule of CaCO3 (2) to find the total number of oxygen atoms.
When limestone (calcium carbonate) is heated, it undergoes thermal decomposition to produce calcium oxide (quicklime) and carbon dioxide gas. The chemical equation for this reaction is: CaCO3 (s) → CaO (s) + CO2 (g).
Calcium carbonate (CaCO3) decomposes into calcium oxide (CaO) and carbon dioxide (CO2) at high temperatures. To maximize decomposition, high temperatures above 800 degrees Celsius and low pressures are ideal. These conditions will promote the breakdown of CaCO3 into its components.
Calcium carbonate is not soluble in water.
2 HCl + CaCO3 = CaCl2 + CO2 + H2O Therefore it takes twice as many moles of HCl to react with CaCO3 Mol CaCO3 = mass / formulae weight = 10 / 40.08 + 14.01 + 3(16.00) = 10 / 102.09 = 0.0980 mol Mol HCl = 2 x 0.0980 = 0.1959 mol Volume HCl = mol / c = 0.1959 / 0.10 = 1.9591 L Volume required to react of HCl = 1.9591 L
1. First of all there is a 1:1 molar ratio. 2. 1000g CaCO3 3. Mass divided Mol Wt = 10 mols (CaCO3 = 100 g/mol) 4. 10 mols CaCO3 produces 10 mols CO2 5. Ideal Gas Law is PV = nRT P = Pressure = 1.03 ATM V = Is what you are solving for n = mols of CO2 = 10 R = Gas Law Constant (look it up either on the web or books in the units you are working with - ATM, celsius, liters OR convert them into something you do have) 6. Plug in the numbers and solve for V in liters - You're Done !
The molar mass of CaCO3 is 100.09 g/mol, and the molar mass of CO2 is 44.01 g/mol. By using stoichiometry, you can calculate that 15.2 grams of CaCO3 would produce 6.51 grams of CO2. Using the ideal gas law, you can then convert the mass of CO2 to volume using its molar volume at STP (22.4 L/mol). The volume of CO2 produced would be around 3.32 liters.
Assuming complete reaction, the molar mass of CaCO3 is approximately 100.09 g/mol. One mole of CaCO3 produces one mole of CO2. Therefore, 10 grams of CaCO3 will produce approximately 2.24 liters of CO2 at STP (22.4 L/mol).
Molar mass of CaCO3 = 66.1221g CaCO3/mole CaCO3. This means that 1 mole CaCO3 = 66.1221g CaCO3. To find the mass of 4.5 mole CaCO3, complete the following calculation: 4.5g CaCO3 X 1mol CaCO3/66.1221g CaCO3 = 0.068 mole CaCO3.
The salt with the greatest solubility in water is sodium chloride (NaCl). Sodium chloride is highly soluble in water due to its strong ionic bonds that readily break apart in water molecules, allowing it to dissociate into Na+ and Cl- ions.
To find the mass of CaCO3 required to react with 100 mL of 2 M HCl, you need to first calculate the number of moles of HCl using its molarity and volume. Then, use the balanced chemical equation to determine the mole ratio between HCl and CaCO3, allowing you to calculate the mass of CaCO3 needed.
It is CaCO3.....it is the same as marbleFormula: CaCO3
caco3 is solid form. its density is high so caco3 is not soluble in water. but co2 mix in water befuor the mix in caco3 . so caco3 is soluble after mixing the co2 .
the answer is DECOMPOSITION... and that is the answer not CaCO3