#6 AWG
50sqmm Al cable can carry 60 amps safely up to 150mtrs. If distance increases size should increase
The voltage drop in a wire has nothing to do with the insulation. Voltage drop has to do with the cross sectional area of the wire.
This is a voltage drop question. To answer this question a voltage has to be stated. The higher the voltage to the circuit becomes the smaller the wire size needed. After a certain voltage point the wire size will remain constant and the voltage drop at the load will become smaller.
To calculate the wire size, a system voltage is needed.
Wire size is based of the amperage of the device. To answer this question the amperage is needed or the wattage and voltage of the device.
Without the amperage the device uses this question can not be answered. The size of wire depends upon the amount of amperage a device draws. The voltage is independent of the size of the wire, it is an insulation factor. Most commonly used wire is rated at 300 volts.
A 10 mm cable is most commonly used for a 500 KVA transformer, 240 volt, 3 phrase. The size of the wire that is used in a transformer is based on the voltage.
To calculate voltage drop to size the wire, a voltage must be stated.
In North America you would use a three wire cable. A dryer needs two voltage supplies. A 240 voltage for the heating element and 120 volts for the motor and controls. The three wire cable will have a ground wire in it also but in North America this is not counted as it is not a current carrying conductor. The size of the cable will be a 3C #10.
It is mandatory to use a larger wire size to overcome voltage drop at the load.
The voltage drop in a wire has nothing to do with the insulation. Voltage drop has to do with the cross sectional area of the wire.
Need to know the wire size of the core conductors.
3r x 300sq.mm Al. ar UG cable <<>> Wiring is sized by the amperage that is used by the load. The formula for amps is I = W/E. Amps = Watts (or VA)/Volts. As you can see an answer can not be given unless a voltage is stated. The lower the primary voltage the larger the amperage will be and likewise the larger the wire size will be.
As with any electrical installation, the wire size used depends on the expected maximum current the wire will carry. That cannot be determined by voltage alone.
You need also to know the resistance of the cable. First you establish what the current of the load is. Then from that you calculate the wire size. From a wire size chart you find the wire resistance. Then use the formula I (squared) x R.
To answer this question a voltage needs to be stated. Wire sizing is based on amperage that the wire can safely conduct. I = W/E. Amps = Watts/Volts.
Depends upon the voltage. The formula for amperage or (wire size) is Watts / Voltage. If the voltage is 220 volts, then the amperage would be over 400 amps. This would require a large wire size to run it. If it were 440 volts, the amperage would be 1/2 or 200 amps. That would require a smaller wire size. As the voltage goes up, the amperage goes down. At a thousand volts, the amperage would only be 90 amps. A wire gauge or size of a #2 would carry 90 amps for small distances.
First of all find out what voltage the motor is designed to work on.