#6 AWG
50sqmm Al cable can carry 60 amps safely up to 150mtrs. If distance increases size should increase
Yes, armored cable can be used to wire 277 volt lights. However, be sure to select the appropriate type and size of armored cable rated for the voltage and current requirements of the lighting system to ensure safety and compliance with electrical codes and regulations.
Wire sizes and ampacity are regulated by code. # 14 wire 15 amps, #12 wire 20 amps, #10 wire 30 amps, #8 wire 40 amps, #6 wire 60 amps. These are the most common, a slight variation in amperage depending on the insulation factor.
For a 37 kW induction motor, a cable size of approximately 10 AWG (American Wire Gauge) would be suitable for typical installations. However, the specific cable size required would depend on factors such as the length of the cable run, ambient temperature, and voltage drop considerations. It is recommended to consult with a qualified electrician to determine the appropriate cable size for your specific application.
You didn't specify the voltage that you are using but here is a simple easy to read chart that may meet your needs: http://www.fennelfamily.com/gti-vr6/electrical/cable-length.html You can google "wire gauge distance" for more charts. Be careful and good luck!
In North America the voltage ratings of low voltage wire comes in three voltages. The voltages are 300, 600 and 1000 volt insulation ratings.
A 10 mm cable is most commonly used for a 500 KVA transformer, 240 volt, 3 phrase. The size of the wire that is used in a transformer is based on the voltage.
To calculate voltage drop to size the wire, a voltage must be stated.
In North America you would use a three wire cable. A dryer needs two voltage supplies. A 240 voltage for the heating element and 120 volts for the motor and controls. The three wire cable will have a ground wire in it also but in North America this is not counted as it is not a current carrying conductor. The size of the cable will be a 3C #10.
It is mandatory to use a larger wire size to overcome voltage drop at the load.
Need to know the wire size of the core conductors.
3r x 300sq.mm Al. ar UG cable <<>> Wiring is sized by the amperage that is used by the load. The formula for amps is I = W/E. Amps = Watts (or VA)/Volts. As you can see an answer can not be given unless a voltage is stated. The lower the primary voltage the larger the amperage will be and likewise the larger the wire size will be.
Yes, armored cable can be used to wire 277 volt lights. However, be sure to select the appropriate type and size of armored cable rated for the voltage and current requirements of the lighting system to ensure safety and compliance with electrical codes and regulations.
As with any electrical installation, the wire size used depends on the expected maximum current the wire will carry. That cannot be determined by voltage alone.
You need also to know the resistance of the cable. First you establish what the current of the load is. Then from that you calculate the wire size. From a wire size chart you find the wire resistance. Then use the formula I (squared) x R.
To answer this question a voltage needs to be stated. Wire sizing is based on amperage that the wire can safely conduct. I = W/E. Amps = Watts/Volts.
Wire sizes and ampacity are regulated by code. # 14 wire 15 amps, #12 wire 20 amps, #10 wire 30 amps, #8 wire 40 amps, #6 wire 60 amps. These are the most common, a slight variation in amperage depending on the insulation factor.
Depends upon the voltage. The formula for amperage or (wire size) is Watts / Voltage. If the voltage is 220 volts, then the amperage would be over 400 amps. This would require a large wire size to run it. If it were 440 volts, the amperage would be 1/2 or 200 amps. That would require a smaller wire size. As the voltage goes up, the amperage goes down. At a thousand volts, the amperage would only be 90 amps. A wire gauge or size of a #2 would carry 90 amps for small distances.