3 Litre ( = 6.00 mol / 2.00 mol/L )
The molarity of the KNO3 solution is 0.544 M. This is calculated by dividing the moles of KNO3 (1.1 mol) by the total solution volume in liters.
To calculate the volume, first find the number of moles of potassium hydroxide using its molar mass. Then use the molarity to calculate the volume. Calculate moles of KOH: 10.7g / 56.11g/mol = 0.191 moles KOH Volume = moles / Molarity = 0.191 moles / 0.550 mol/L = 0.348 L = 348 mL
The molarity of the sugar solution can be calculated using the formula: molarity = moles of solute / liters of solution. Plugging in the values, molarity = 21.0 moles / 52.0 L which equals 0.404 Molarity.
Adding 4.5 moles of NH3 to 250 mL of water will result in a solution with a volume slightly greater than 250 mL. To calculate the molarity, you need to know the final volume of the solution. Once you have the final volume, you can use the formula: Molarity = moles of solute / liters of solution.
Molarity (M) is defined as moles of solute/liters of solution. Assuming the final volume is 500 ml (0.5 liters), then M = 1.2 moles/0.5 liters = 2.4 M
The molarity of the solution would be approximately 0.2 M. This is calculated by first converting the mass of water to volume (10 kg is roughly equivalent to 10 L), then using the formula Molarity = moles of solute / volume of solution in liters.
First, calculate the molar mass of FeCl3: 162.2 g/mol. Next, calculate the number of moles of FeCl3 in 130 g: 130 g / 162.2 g/mol = 0.801 moles. Finally, use the formula for molarity: Molarity = moles of solute / volume of solution (in liters) to solve for volume. 0.88 M = 0.801 moles / volume, therefore volume = 0.801 moles / 0.88 M ≈ 0.91 L.
To find the concentration of the final solution, you need to calculate the total moles of KOH before and after dilution. The initial moles of KOH can be found using the initial volume and concentration. Then, calculate the final volume of the solution after dilution and use it to determine the final concentration of KOH.
concentration or molarity = number of moles/volume number of moles (n) = mass in grams of nacl/relative atomic mass of nacl n=17.52/(23+35.5) n = 0.2994872 mol volume = 2000/1000 = 2dm^3 molarity = 0.2994872/2 =0.15mol/dm^3
The molarity of the KNO3 solution is 0.544 M. This is calculated by dividing the moles of KNO3 (1.1 mol) by the total solution volume in liters.
To calculate the volume, first find the number of moles of potassium hydroxide using its molar mass. Then use the molarity to calculate the volume. Calculate moles of KOH: 10.7g / 56.11g/mol = 0.191 moles KOH Volume = moles / Molarity = 0.191 moles / 0.550 mol/L = 0.348 L = 348 mL
Need to find moles NaCl. 526 grams NaCl (1 mole NaCl/58.44 grams) = 9.0 moles NaCl --------------------------------now, Molarity = moles of solute/Liters of solution or, for our purposes Liters of solution = moles of solute/Molarity Liters of solution = 9.0 moles NaCl/3.0 M = 3.0 liters in volume ---------------------------------
The molarity of the sugar solution can be calculated using the formula: molarity = moles of solute / liters of solution. Plugging in the values, molarity = 21.0 moles / 52.0 L which equals 0.404 Molarity.
Adding 4.5 moles of NH3 to 250 mL of water will result in a solution with a volume slightly greater than 250 mL. To calculate the molarity, you need to know the final volume of the solution. Once you have the final volume, you can use the formula: Molarity = moles of solute / liters of solution.
6 kg = 6000 grams and density of water = 1.00 grams/milliliters. 1.00 g/ml = 6000 grams/X ml = 6000 ml which = 6 liters ======================== Molarity = moles of solute/Liters of solution Molarity = 2 moles NaOH/6 Liters = 0.3 M NaOH solution -----------------------------
Molarity (M) is defined as moles of solute/liters of solution. Assuming the final volume is 500 ml (0.5 liters), then M = 1.2 moles/0.5 liters = 2.4 M
what is the molarity of a solution prepared by dissolving 36.0g of NaOH in enough water to make 1.50 liter of solution?