The answer is 900 kg.
To determine the heat energy produced when burning propane, we need to know its heat of combustion, which is approximately 50 MJ/kg. For 22 grams (0.022 kg) of propane, the energy released can be calculated as follows: 0.022 kg × 50,000 kJ/kg = 1,100 kJ. Therefore, burning 22 grams of propane produces about 1,100 kJ of heat energy.
The atomic mass of hydrogen is 1.008 and the molecular mass of water, with formula H2O, is 18.015. Therefore, the mass of hydrogen to that of water has the ratio of 2(1.008)/18.015 = about 0.1119, and the answer to the problem is 300/0.1119 = 2.68 X 103 grams, to the justified number of significant digits.
In chemistry, the outcome of a reaction must have the same mass as the initial state. This means that if you have 32g of oxygen and 4g of hydrogen, you just have to add the numbers to discover the original mass (in this case, 36g).
The combustion of hexane (C6H14) produces carbon dioxide (CO2) according to the reaction: C6H14 + 7O2 → 6CO2 + 7H2O. For every 1 gram of hexane burned, approximately 3.03 grams of carbon dioxide are produced. Therefore, from the combustion of B grams of hexane, the amount of carbon dioxide produced would be approximately 3.03B grams.
8.20g of carbon monoxide, how many grams of methanol will be produced?
The equation of the reaction is Fe + HCl → H₂ + FeCl₂. Since one mole of iron produces one mole of hydrogen gas, the molar ratio between Fe and H₂ is 1:1. Thus, the total number of grams of H₂ produced when 116 grams of iron is reacted would be 2 grams (1 mole of hydrogen gas weighs 2 grams).
To determine the heat energy produced when burning propane, we need to know its heat of combustion, which is approximately 50 MJ/kg. For 22 grams (0.022 kg) of propane, the energy released can be calculated as follows: 0.022 kg × 50,000 kJ/kg = 1,100 kJ. Therefore, burning 22 grams of propane produces about 1,100 kJ of heat energy.
The atomic mass of hydrogen is 1.008 and the molecular mass of water, with formula H2O, is 18.015. Therefore, the mass of hydrogen to that of water has the ratio of 2(1.008)/18.015 = about 0.1119, and the answer to the problem is 300/0.1119 = 2.68 X 103 grams, to the justified number of significant digits.
To calculate the amount of CO2 produced when burning 34.3 grams of C3H8 (propane), you need to balance the chemical equation for the combustion of C3H8. Since each mole of C3H8 produces 3 moles of CO2, you first convert 34.3 grams of C3H8 to moles, calculate the moles of CO2 produced, and then convert that to grams of CO2.
To calculate the grams of CO2 produced by burning 22 grams of C3H8, first determine the moles of C3H8 using its molar mass, then use the balanced chemical equation for the combustion of C3H8 to find the moles of CO2 produced, and finally convert moles of CO2 to grams using the molar mass of CO2.
Weight:1.45 grams volume: 6.789
In chemistry, the outcome of a reaction must have the same mass as the initial state. This means that if you have 32g of oxygen and 4g of hydrogen, you just have to add the numbers to discover the original mass (in this case, 36g).
The gram molecular mass of HCl is 36.46 and the gram atomic mass of hydrogen atoms is 1.008. Therefore 146 grams of HCl decompose to provide 146(1.008/36.46) or about 4.04 grams of hydrogen gas, to the justified number of significant digits.
Cu + 2 HCl --> CuCl2 + H2 167.12 g HCl * (1 mol HCl/36.46 g HCl) * (1 mol H2/2 mol HCl) * (2.02 g/1 mol H2) = 4.629 g H2 4.63 grams of hydrogen gas is produced when 167.12 grams of hydrochloric acid reacts with copper.
an equation showing conservation of mass of reactants and products:2H2O --> 2H2 & O2what is the mass of the oxygen gas produced, from 178.8 g H2O , (using molar masses:178.8 g H2O @ (1mol O2)(@ 32.00 g/mol) / (2molH2O)(18.02g/mol) =your answer (4 sigfigs): 158.8 g O2178.8 g H2O ---> 20.0 H2 & 158.8 O2
The molar mass of calcium hydride is 42.094 g/mol. Each mole of calcium hydride produces 2 moles of hydrogen gas. First, calculate the number of moles of hydrogen gas produced by 8.700 g of hydrogen, then use stoichiometry to find the mass of calcium hydride required.
If 15 liters of propane are completely consumed 90,25 grams of carbon dioxide are produced.