The answer is 900 kg.
The atomic mass of hydrogen is 1.008 and the molecular mass of water, with formula H2O, is 18.015. Therefore, the mass of hydrogen to that of water has the ratio of 2(1.008)/18.015 = about 0.1119, and the answer to the problem is 300/0.1119 = 2.68 X 103 grams, to the justified number of significant digits.
The mass of water that decomposes to produce 4 grams of hydrogen gas and 32 grams of oxygen gas is 36 grams. This is because the molar ratio of hydrogen to oxygen in water is 2:1, so for every 2 grams of hydrogen produced, 16 grams of oxygen are produced. Thus, to produce 4 grams of hydrogen and 32 grams of oxygen, a total of 36 grams of water must have decomposed.
8.20g of carbon monoxide, how many grams of methanol will be produced?
8 grams. Or more exactly, in 30.0 grams of methane there is 7.54 grams of hydrogen.
45,0 grams of hydrogen gas have 135,5.10e23 atoms.
The equation of the reaction is Fe + HCl → H₂ + FeCl₂. Since one mole of iron produces one mole of hydrogen gas, the molar ratio between Fe and H₂ is 1:1. Thus, the total number of grams of H₂ produced when 116 grams of iron is reacted would be 2 grams (1 mole of hydrogen gas weighs 2 grams).
The atomic mass of hydrogen is 1.008 and the molecular mass of water, with formula H2O, is 18.015. Therefore, the mass of hydrogen to that of water has the ratio of 2(1.008)/18.015 = about 0.1119, and the answer to the problem is 300/0.1119 = 2.68 X 103 grams, to the justified number of significant digits.
To calculate the amount of CO2 produced when burning 34.3 grams of C3H8 (propane), you need to balance the chemical equation for the combustion of C3H8. Since each mole of C3H8 produces 3 moles of CO2, you first convert 34.3 grams of C3H8 to moles, calculate the moles of CO2 produced, and then convert that to grams of CO2.
To calculate the grams of CO2 produced by burning 22 grams of C3H8, first determine the moles of C3H8 using its molar mass, then use the balanced chemical equation for the combustion of C3H8 to find the moles of CO2 produced, and finally convert moles of CO2 to grams using the molar mass of CO2.
Weight:1.45 grams volume: 6.789
The mass of water that decomposes to produce 4 grams of hydrogen gas and 32 grams of oxygen gas is 36 grams. This is because the molar ratio of hydrogen to oxygen in water is 2:1, so for every 2 grams of hydrogen produced, 16 grams of oxygen are produced. Thus, to produce 4 grams of hydrogen and 32 grams of oxygen, a total of 36 grams of water must have decomposed.
The gram molecular mass of HCl is 36.46 and the gram atomic mass of hydrogen atoms is 1.008. Therefore 146 grams of HCl decompose to provide 146(1.008/36.46) or about 4.04 grams of hydrogen gas, to the justified number of significant digits.
Cu + 2 HCl --> CuCl2 + H2 167.12 g HCl * (1 mol HCl/36.46 g HCl) * (1 mol H2/2 mol HCl) * (2.02 g/1 mol H2) = 4.629 g H2 4.63 grams of hydrogen gas is produced when 167.12 grams of hydrochloric acid reacts with copper.
The total mass of water is 178.8 grams. If 20.0 grams of hydrogen gas is produced, then the mass of oxygen gas produced can be calculated by subtracting the mass of hydrogen from the total mass of water: 178.8g - 20.0g = 158.8 grams. Therefore, the mass of oxygen gas produced is 158.8 grams.
The molar mass of calcium hydride is 42.094 g/mol. Each mole of calcium hydride produces 2 moles of hydrogen gas. First, calculate the number of moles of hydrogen gas produced by 8.700 g of hydrogen, then use stoichiometry to find the mass of calcium hydride required.
When 15 liters of propane are completely burned, it produces 110 grams of carbon dioxide.
To determine the limiting reactant, we need to find the moles of each reactant. Then, we calculate the amount of ammonia that can be produced from each reactant. Whichever reactant produces the least amount of ammonia is the limiting reactant. Finally, we calculate the grams of ammonia produced based on the limiting reactant.