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When there is more than one polyatomic ion. Calcium Hydroxide is an example. Ca has a charge of 2+ and OH has a charge of 1-. To make this neutral, 2 hydroxides are required. So it would be written: Ca(OH)2. If we didn't use the parentheses, it would look like there was 1 calcium, 1 oxygen, and 2 hydrogens. Obviously this isn't right. That's why the parentheses are necessary.
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BlakeParentheses in a formula are used to indicate the order of operations, just like in arithmetic. They ensure that certain calculations are performed first before others. Parentheses help to clarify the hierarchy of operations in a formula and prevent confusion about which calculations should be done together.
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Why do you put parentheses around a polyatomic ion?
Parentheses around a polyatomic ion in a chemical formula indicates that more than one of that ion is present in the compound. This notation helps clarify the chemical formula and the ratio of elements in the compound.
What do parentheses around a group of atoms in a chemical formula indicate?
Something like (C10H8O4)n? (This is the formula for the plastic a Coke bottle is made of.) It means there are multiple instances of whatever group is inside the parentheses.
Why are parentheses used in formulas?
Parentheses in formulas are used to establish the order of operations. They help clarify which operations should be performed first and ensure that the formula is evaluated correctly. Without parentheses, the formula could produce a different result than intended.
How many atoms does a molecule contain?
The number of atoms in a molecule can vary depending on the type of molecule. Molecules can contain as few as two atoms (diatomic molecules) or as many as hundreds or thousands of atoms (complex organic molecules).
Why are parentheses used to write the formula for AlOH3?
Parentheses are used for the formula Al(OH)3 to indicate that the hydroxide group (OH) is grouped together and that there are three of them bonded to the aluminum atom. This notation helps to clarify the composition and structure of the compound.
