Mg3(C6H5O7)2 is the molecular formula for magnesium citrate. Magnesium is a Group IIA element and like all members of this group readily ionizes to Mg+2. C6H5O7 is the formula for the polyatomic citrate ion which has a negative three charge. Molecules are stable combination of atoms that are electronically neutral. It takes three Mg+2 to cancel out the charge of two C6H5O7-3.
Parenthesis are placed around the citrate ion to show that the subscript 2 only applies to the citrate ion.
The chemical formula for magnesium phosphate is Mg3(PO4)2. This mineral is very important and keeps the human body working properly.
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The formula for the manganese (III) ion is Mn3+. The charge on the manganese ion is +3.
The correct formula for magnesium phosphate is Mg3(PO4)2. This is because magnesium has a 2+ charge (Mg2+) and phosphate has a 3- charge (PO43-). To balance the charges in the compound, you need three magnesium ions (3 x 2+ = 6+) to combine with two phosphate ions (2 x 3- = 6-), resulting in the formula Mg3(PO4)2.
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The balanced chemical equation for the reaction between magnesium and citric acid is: 3 Mg + 2 C6H8O7 -> Mg3(C6H5O7)2 + 3 H2.
Po4(aq) + 3Mg (aq) equals Mg3(Po4)2 (s)
The formula for magnesium phosphate is Mg3(PO4)2. This compound contains three magnesium ions (Mg^2+) and two phosphate ions (PO4^3-).
The chemical formula for magnesium phosphate is Mg3(PO4)2. This mineral is very important and keeps the human body working properly.
The reaction is:3 MgSO4 + 2 Na3PO4 = Mg3(PO4)2 + 3 Na2SO4
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3Mg(s) + 2H3PO4(aq) ---> 3H2(g) + Mg3(PO4)2(s)I believe the equation is: Mg + H3PO4 ---> H2 + Mg3PO4. It should be Mg3(PO4)2 because magnesium has a charge of +2 (Mg+2), and phosphate has a charge of -3 (PO4-3), which would become Mg3(PO4)2. Balanced, the equation is 3Mg + 2H3PO4 ---> 3H2 + Mg3(PO4)2
Magnesium phosphate (Mg3(PO4)2) is an ionic compound. It is composed of positively charged magnesium ions (Mg^2+) and negatively charged phosphate ions (PO4^3-), which are held together by ionic bonds.
The net ionic equation for this reaction is:3Mg2+(aq) + 2PO43-(aq) -->Mg3(PO4)2(s)How to get this answer:To write the net ionic equation, you can start with the molecular equation:2Na3PO4(aq) + 3Mg(NO3)2(aq) --> 6NaNO3(aq) + Mg3(PO4)2(s)The molecular equation can be used to write the full ionic equation. To do this, you break down everything that is aqueous into its ionic constituents:2Na+(aq) + 2PO43-(aq) + 3Mg2+(aq) + 6NO3-(aq) --> 6Na+(aq) + 6NO3-(aq) + Mg3(PO4)2(s)You can then cross out whatever is the same on both side to get your net ionic equation:3Mg2+(aq) + 2PO43-(aq) -->Mg3(PO4)2(s)
The formula for the manganese (III) ion is Mn3+. The charge on the manganese ion is +3.
If you balance the charges of the magnesium ion and the phosphate polyatomic ion, you get a formula of Mg3(PO4)2. Now count 'em up: there are 3 magnesiums, 2 phosphrous, and 8 oxygens. (watch those parentheses!)
There is more than one compound between magnesium and phosphate, but the most common one has a formula of Mg3(PO4)2. This formula unit contains 13 atoms: 3 of magnesium, 2 of phosphorus, and 8 of oxygen.