Well, darling, to solve this little equation, you simply need to isolate the variable x. First, you'll want to subtract 9 from both sides to get -5x = -5. Then, divide by -5 on both sides to find x = 1. Voilà, problem solved!
5x + 4 - 3x + 5 + 2x - 9 = 4x
25x2 + 40x + 16 = 25x2 + 20x + 20x + 16 = 5x(5x + 4) + 4(5x + 4) = (5x + 4)(5x + 4) or (5x + 4)2
5x = 5 times 9, 2y = 2 times 4 so 45 - 8 ie 37
5x² - 18x + 9 = (5x² - 15x) - (3x - 9) = 5x(x - 3) - 3(x - 3) = (5x - 3)(x - 3).
5x - 9 = 4x 5x - 4x - 9 = 4x - 4x x - 9 = 0 x - 9 + 9 = 0 + 9 x = 9
4(5x + 3) - 9 = 20x + 3
if you mean 5x-4-3x=9 then x= 6.5
(5x+4)(9x+9) FOIL First (5x*9x=45x**2) Outside (5x*9=45x) Inside (4*9x=36x) Last (4*9=36) 45x**2+45x+36x+36 45x**2+81x+36 9(5x**2+9x+4x)
5x + 4 = 10x - 5 10x - 5x = 4 + 5 5x = 9 x = 1.8
9
y - 9 = -5(x - 4) y - 9 = -5x + 20 y = -5x +20 +9 y = -5x +29
5x + 9 = 4Subtract 9 from each side:5x = -5Divide each side by 5:x = -1
5x + 4 - 3x + 5 + 2x - 9 = 4x
9
-4
5x-9Substitute 4 in for x5(4)-9=Solve.9-9=0the answer is zero.The answer is not zero you added when you were supposed to multiply so the real answer is 11.
To answer this question we need to first get the slope of the line 5x-4y=9 by rearranging it in the form of y=mx+b: 5x-4y=9 4y=5x-9 y=(5/4)x-9/4 Since the slope of parallel lines are negative reciprocals of each other, the negative reciprocal of 5/4 is -4/5, therefore the slope of a line parallel to the line 5x-4y=9 is -4/5