The antiderivative of a function which is equal to 0 everywhere is a function equal to 0 everywhere.
The fundamental theorum of calculus states that a definite integral from a to b is equivalent to the antiderivative's expression of b minus the antiderivative expression of a.
-e-x + C.
-1
You can't, unless it's an initial value problem. If f(x) is an antiderivative to g(x), then so is f(x) + c, for any c at all.
The antiderivative of 2x is x2.
The antiderivative of a function which is equal to 0 everywhere is a function equal to 0 everywhere.
No It is not 5x4=20 and 5x100=500
5x4 meters = 20m2 = 215.28 square feet.
35x2
Using u-substitution (where u = sinx), you'll find the antiderivative to be 0.5*sin2x + C.
I assume you mean -10x^4? In that case, antiderivative would be to add one to the exponent, then divide by the exponent. So -10x^5, then divide by 5. So the antiderivative is -2x^5.
Antiderivative of x/-1 = -1(x^2)/2 + C = (-1/2)(x^2) + C Wolfram says antiderivative of x^-1 is log(x) + C
By antiderivative do you mean integral? If yes, integral x^1 dx= (x^2)/2
something like 5x4=4x5.
The lug pattern for 69 Dart is 5x4" original.
The Commutative Property (of Multiplication) says that 4x5 = 5x4. So, If 4x5 = 20, then 5x4 will also be 20.