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6 goes into 117 a total of 19 times. This can be calculated by dividing 117 by 6, which equals 19 with a remainder of 3. Therefore, 6 goes into 117 exactly 19 times.
1 x 117, 3 x 39, 9 x 13 = 117
If limited to integer solutions, the answers are: 1*117, 3*39 and 9*13
117x1, 39x3, 13x9