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Assuming that is 7.25% APR, then, as it's compound interest:
amount = 1000 x (1 + 7.25%)^2 = 1000 x (1 + 7.25/100)^2 = 1000 x 1.0725^2 ≈ 1150.26
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How much would 2000 become in 10 years at 5 percent interest?
If it is not compounded the interest would be 2000x10x.05=1000 If it is compounded then it is different.
How many years will it take for a 50 investment to grow to 1000 if it is compounded continuously at a rate of 5 percent?
59.91
Approximately how long will it take for 1000 to grow to 5006 at 8 annual interest and compounded 12 times per year?
Use the equation $=$0*(1 + r)xn where $ is the amount of money, $0 is the initial amount of money, r is the rate, x is the number of times per year the interest is compounded, and n is the number of years the interest is compounded. We are solving for n. To do this we need to use logs. log(1 + r)($/$0)/x = n log1.08(5006/1000)/12 = n = 1.744 years.
What is the future value of 1000 invested at 8 percent for 7 years?
Future value = 1000*(1.08)7 = 1713.82
Jon deposits 1000 in an account that pays 8 percent interest compounded annually How long will it take to double your money?
1). My money will never double. Let's talk about Jon's money instead. 2). It doesn't matter how much he deposits into the account. The time required for it to double is the same in any case. 3). At 8% interest compounded annually, the money is very very very nearly ... but not quite ... doubled at the end of 9 years. At the end of the 9th year, the original 1,000 has grown to 1,999.0046. If the same rate of growth were operating continuously, then technically, it would take another 2days 8hours 38minutes to hit 2,000. But it's not growing continuously; interest is only being paid once a year. So if Jon insists on waiting for literally double or better, then he has to wait until the end of the 10th year, and he'll collect 2,158.92 .
What is the formula to calculate 1000 invested at 8 percent for 5 years?
Assuming interest is compounded annually, 1000*(1.08)5
What would the value of 1000 in 1921 be today gaining 10 percent interest?
$1000 compounded at 10% annually over 86 years would be almost $4,000,000.
Matthew invests 1000 at 8 percent compounded annually for 2 years Find the compound interest?
Total after 2 years = 1000*(1.08)2 = 1000*1.1664 =1166.40 So interest = Total - Inirial capital = 1166.40 -1000 = 166.40
How much would 2000 become in 10 years at 5 percent interest?
If it is not compounded the interest would be 2000x10x.05=1000 If it is compounded then it is different.
How much would 6 percent interest be on 1000 compounded over four years?
Total = 1000(1+0.06)4 = 1262.48
How many years will it take for a 50 investment to grow to 1000 if it is compounded continuously at a rate of 5 percent?
59.91
What is the future value of 1000 dollars in 4 years at interest rate of 5 percent compounded semiannually?
1000 x (1.025)8 which is $1218.40.
The future value of a 1000 investment today at 8 percent annual interest compounded semiannually for 5 years is?
$1480.24
What does it mean when they say interest compounded semi annually?
It is compounded twice a year. The formula is A=P(1+rt) P is how much is put in, r is the percentage as a decimal, t is how many times it is compounded a year so in this case it would be 2. So if deposited $1000 in a bank at 8% that is compounded semi annually, the formula would look like this. A=$1000(1+.08(2))
How long will it take to increase an intitial investment of 1000 to 8000 at an annual rate of 10 percent?
If compounded, it will take 21.818 years.
To how much will 1000 grow to if it is invested at 12 percent per annum for nine years compounding annually?
1000*(1 + 12/100)9 = 1000*(1.12)9 = 2773.08
A bank account yields 7 percent interest compounded annually If you deposit 1000 in the account what will the account balance be after five years?
Per annum compound interest formula: fv = pv(1+r)^t Where: fv = future value pv = present (initial) value r = interest rate t = time period Thus, fv = 1000*(1+0.07)^5 = 1000*1.4025517307 = $1402.55
