Assuming that is 7.25% APR, then, as it's compound interest:
amount = 1000 x (1 + 7.25%)^2 = 1000 x (1 + 7.25/100)^2 = 1000 x 1.0725^2 ≈ 1150.26
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If it is not compounded the interest would be 2000x10x.05=1000 If it is compounded then it is different.
59.91
Use the equation $=$0*(1 + r)xn where $ is the amount of money, $0 is the initial amount of money, r is the rate, x is the number of times per year the interest is compounded, and n is the number of years the interest is compounded. We are solving for n. To do this we need to use logs. log(1 + r)($/$0)/x = n log1.08(5006/1000)/12 = n = 1.744 years.
Future value = 1000*(1.08)7 = 1713.82
1). My money will never double. Let's talk about Jon's money instead. 2). It doesn't matter how much he deposits into the account. The time required for it to double is the same in any case. 3). At 8% interest compounded annually, the money is very very very nearly ... but not quite ... doubled at the end of 9 years. At the end of the 9th year, the original 1,000 has grown to 1,999.0046. If the same rate of growth were operating continuously, then technically, it would take another 2days 8hours 38minutes to hit 2,000. But it's not growing continuously; interest is only being paid once a year. So if Jon insists on waiting for literally double or better, then he has to wait until the end of the 10th year, and he'll collect 2,158.92 .