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What else can I help you with?
What is the weight of 1 meter length of 10 mm tor steel?
8mm dia : 0.395 kg/m 10mm dia : 0.617 kg/m 12mm dia : 0.888 kg/m 16mm dia : 1.579 kg/m 20mm dia : 2.467 kg/m 25mm dia : 3.855 kg/m These are standard unit weights based on the density of steel @ 7850 kg/m3
What is the density of a bowling ball with a mass of 3.0 kg and a volume of 0.0050 m3?
It is 3.0/0.0050 = 60 kg per m^3.
What is m plus m plus 5?
510 cm or 5.10 m
1200square meters equals how many feet square?
Answer: 1200 m² = 12,916.692 ft²
In what unit of measure do you measure momentum?
kg-m/s
A 75 kg speed skater moving forward at 16 m s?
The speed skater has a momentum of 1200 kg*m/s.
What is the momentum of a van with a mass of 1200 kg traveling at a speed of 25 m s?
Simply multiply the mass and the speed. The answer will be in kg x m / s. As far as I know, this unit has no special name. Momentum is a vector; the direction of the momentum vector will, of course, be in the direction of the movement.
How much force would be required to accelerate a 1200 kg car at a rate of 5 m Per Second Squared?
F = M A = (1200) (5) = 6,000 newtons
What is the weight of a 1200 kg truck?
The weight of a 1200 kg truck is approximately 12000 N (Newtons) on Earth's surface, assuming standard gravity of 9.81 m/s^2.
Collision-sample problems with solutions and answer?
Sure, here are some sample collision problems with solutions: Problem: Two cars collide at an intersection. Car A has a mass of 1500 kg and is moving at 25 m/s, while Car B has a mass of 1200 kg and is stationary. After the collision, Car A is moving at 10 m/s. Calculate the final velocity of Car B. Solution: From the principle of conservation of momentum, we have: (1500 kg)(25 m/s) + (1200 kg)(0 m/s) = (1500 kg)(10 m/s) + (1200 kg)(v) 37500 kgm/s = 15000 kgm/s + 1200 kg *v v = 25 m/s Problem: A billiard ball with a mass of 0.2 kg moving at 3 m/s collides with another ball of mass 0.3 kg at rest. After the collision, the first ball is at rest and the second ball moves at 2 m/s. Calculate the final velocity of the first ball. Solution: Using the principle of conservation of momentum: (0.2 kg)(3 m/s) + (0.3 kg)(0 m/s) = (0.2 kg)(0 m/s) + (0.3 kg)(2 m/s) 0.6 kg.m/s = 0.6 kg.m/s Therefore, the final velocity of the first ball is 0 m/s.
How many miles is 1200 yards?
1200 yards = 0.681818182 miles
How much force is needed to accelerate a 1200 kg car at a rate of 1.8 ms2?
The force needed to accelerate the car can be calculated using Newton's second law: Force = mass x acceleration. Plugging in the values, we get: Force = 1200 kg x 1.8 m/s^2 = 2160 N. So, 2160 Newtons of force is needed to accelerate the 1200 kg car at a rate of 1.8 m/s^2.
How much tension must a rope withstand if it is used to accelerate a 1900 kg car vertically upward at 0.80 ms2?
F = mg + ma F = (1200)(9.8) + (1200)(0.90) F = (1200)(9.8 + 0.9)
A car has a mass of 1200 kg. What is its acceleration when the engine exerts a force of 600 N (Formula Fma)?
The acceleration of the car can be calculated using the formula F=ma, where F is the force applied (600 N) and m is the mass of the car (1200 kg). Rearranging the formula to solve for acceleration gives a = F/m. Therefore, the acceleration of the car is 0.5 m/s^2.
How do you add 12meters plus 15meters plus 81cm plus 65cm?
1200 + 1500 + 81 + 65 = 2846 cm = 28 m, 46 cm
If the mass of an object on earth is 1200 newtons what is it on the moon?
To find the mass of an object, you can use the formula ( \text{Weight} = \text{mass} \times \text{gravity} ). On Earth, the gravitational acceleration is approximately 9.81 m/s², so a weight of 1200 newtons corresponds to a mass of about 122.4 kg (1200 N ÷ 9.81 m/s²). On the Moon, where the gravitational acceleration is about 1.62 m/s², the weight of that same mass would be approximately 199.3 newtons (122.4 kg × 1.62 m/s²).
What is the kinetic energy of a car with a mass 1200 kg car moving at velocity of w ms?
The kinetic energy of the car can be found using the formula (KE = \frac{1}{2} m v^2), where (m = 1200) kg (mass of the car) and (v = w) m/s (velocity of the car). Substituting the values into the formula, the kinetic energy of the car would be (KE = \frac{1}{2} \times 1200 \times w^2) J.
