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What is the weight of 1 meter length of 10 mm tor steel?
8mm dia : 0.395 kg/m 10mm dia : 0.617 kg/m 12mm dia : 0.888 kg/m 16mm dia : 1.579 kg/m 20mm dia : 2.467 kg/m 25mm dia : 3.855 kg/m These are standard unit weights based on the density of steel @ 7850 kg/m3
What is the density of a bowling ball with a mass of 3.0 kg and a volume of 0.0050 m3?
It is 3.0/0.0050 = 60 kg per m^3.
What is m plus m plus 5?
510 cm or 5.10 m
1200square meters equals how many feet square?
Answer: 1200 m² = 12,916.692 ft²
In what unit of measure do you measure momentum?
kg-m/s
A 75 kg speed skater moving forward at 16 m s?
The speed skater has a momentum of 1200 kg*m/s.
What is the momentum of a van with a mass of 1200 kg traveling at a speed of 25 m s?
Simply multiply the mass and the speed. The answer will be in kg x m / s. As far as I know, this unit has no special name. Momentum is a vector; the direction of the momentum vector will, of course, be in the direction of the movement.
How much force would be required to accelerate a 1200 kg car at a rate of 5 m Per Second Squared?
F = M A = (1200) (5) = 6,000 newtons
What is the weight of a 1200 kg truck?
The weight of a 1200 kg truck is approximately 12000 N (Newtons) on Earth's surface, assuming standard gravity of 9.81 m/s^2.
Spaceship 1 and spaceship 2 have equal masses of 200 kg spaceship 1 has a speed of 0 ms and spaceship 2 has a speed of 6 ms If they collide and stick together what is the combined momentum?
The momentum of an object is calculated by multiplying its mass by its velocity. For spaceship 1, the momentum is (200 , \text{kg} \times 0 , \text{m/s} = 0 , \text{kg m/s}). For spaceship 2, the momentum is (200 , \text{kg} \times 6 , \text{m/s} = 1200 , \text{kg m/s}). Therefore, the combined momentum after the collision, when they stick together, is (0 + 1200 = 1200 , \text{kg m/s}).
Collision-sample problems with solutions and answer?
Sure, here are some sample collision problems with solutions: Problem: Two cars collide at an intersection. Car A has a mass of 1500 kg and is moving at 25 m/s, while Car B has a mass of 1200 kg and is stationary. After the collision, Car A is moving at 10 m/s. Calculate the final velocity of Car B. Solution: From the principle of conservation of momentum, we have: (1500 kg)(25 m/s) + (1200 kg)(0 m/s) = (1500 kg)(10 m/s) + (1200 kg)(v) 37500 kgm/s = 15000 kgm/s + 1200 kg *v v = 25 m/s Problem: A billiard ball with a mass of 0.2 kg moving at 3 m/s collides with another ball of mass 0.3 kg at rest. After the collision, the first ball is at rest and the second ball moves at 2 m/s. Calculate the final velocity of the first ball. Solution: Using the principle of conservation of momentum: (0.2 kg)(3 m/s) + (0.3 kg)(0 m/s) = (0.2 kg)(0 m/s) + (0.3 kg)(2 m/s) 0.6 kg.m/s = 0.6 kg.m/s Therefore, the final velocity of the first ball is 0 m/s.
How many miles is 1200 yards?
1200 yards = 0.681818182 miles
How much force is needed to accelerate a 1200 kg car at a rate of 1.8 ms2?
The force needed to accelerate the car can be calculated using Newton's second law: Force = mass x acceleration. Plugging in the values, we get: Force = 1200 kg x 1.8 m/s^2 = 2160 N. So, 2160 Newtons of force is needed to accelerate the 1200 kg car at a rate of 1.8 m/s^2.
How much tension must a rope withstand if it is used to accelerate a 1900 kg car vertically upward at 0.80 ms2?
F = mg + ma F = (1200)(9.8) + (1200)(0.90) F = (1200)(9.8 + 0.9)
A car has a mass of 1200 kg. What is its acceleration when the engine exerts a force of 600 N (Formula Fma)?
The acceleration of the car can be calculated using the formula F=ma, where F is the force applied (600 N) and m is the mass of the car (1200 kg). Rearranging the formula to solve for acceleration gives a = F/m. Therefore, the acceleration of the car is 0.5 m/s^2.
If the mass of an object on earth is 1200 newtons what is it on the moon?
To find the mass of an object, you can use the formula ( \text{Weight} = \text{mass} \times \text{gravity} ). On Earth, the gravitational acceleration is approximately 9.81 m/s², so a weight of 1200 newtons corresponds to a mass of about 122.4 kg (1200 N ÷ 9.81 m/s²). On the Moon, where the gravitational acceleration is about 1.62 m/s², the weight of that same mass would be approximately 199.3 newtons (122.4 kg × 1.62 m/s²).
How do you add 12meters plus 15meters plus 81cm plus 65cm?
1200 + 1500 + 81 + 65 = 2846 cm = 28 m, 46 cm
