To solve this problem, you must make equivilent fractions. What this means is you need to make the denominators of the two fractions the same. You need to find the least common multiple of 13 and 8. In this case, this number is 104. So, now we take the fraction 12 over 13, and multiply. To get 104 as the denominator you need to multiply 13*8. Then, since you multiplied the denominator by 8, you need to multiply the numerator by 8 as well. 12*8 is 96, so your new fraction is 96 over 104. Now, to get the denominator of 104 in 7 over 8, you need to multiply 8*13. Now, you need to multiply 7*13 as well. Your new fraction is 91/104. Now you add the numerators. 96+91=187. Your answer is 187 over 104. This is an improper fraction, which you need to convert to a mixed number. To do this, figure out how many times 104 goes into 187, which is one time. Now see how much is left over, which in this case is 83. So 83 is your numerator, and you keep the same denominator. So your answer is 1 and 83 over 104.
13/13 + 12/14 = 13/7 or 16/7
7/9.
13 + 23 + 12 + 7 = 55
13 + 21 - 7 + 12 = 15
13 and 12/8 = 14 and 1/2
7/8 + 13/24 = (7*3)/(8*3) + 13/24 = 21/24 + 13/24 = 34/24 = 17/12 or 1 5/12
6 + 13 + 2 + 12 + 7 + 14 = 54
12/13 = 96/104 7/8 = 91/104 96/104 + 91/104 = 187/104 or 1 and 83/104
what is d over 12 plus 7 times d over 12 equal
It's impossible for that to happen. 6 plus 7 is 13, not 12.
15/14 x 2/3 = 30/42 or 5/7
83