30
81 + 1 + 1 + 1
1+4+9=14
what is the least possible sum of two 4-digit numbers?what is the least possible sum of two 4-digit numbers?
To express 95 as the sum of four or fewer square numbers, we can use the Lagrange's four-square theorem, which states that any natural number can be expressed as the sum of four integer squares. In this case, 95 can be written as 9^2 + 4^2 + 2^2, which equals 81 + 16 + 4, satisfying Fermat's statement. This demonstrates that 95 can indeed be expressed as the sum of three square numbers.
30
33, 36, 39, 42
25= 5*5 = (3*3)+(4*4)
here are some 144 4 1 1 9 16 25 100 1 36 49 64
There is no particular characteristic that is common to such numbers other than they are positive integers greater than or equal to 4.
The numbers are 3, and 4.
i have two answers: 100+25+16+9=150 16+4+121+9=150
If you have a data set, simply take the square root of the sum of the squares of the data points. Let's say you have three numbers a, b, and c. RSS = SQRT(a2 + b2 + c2).
81 + 1 + 1 + 1
1+4+9=14
This could be the solution to the sum : 12 + 22 = 1 + 4 = 5
12+22+32+42+52+62 = 1+4+9+16+25+36= 91