It is increasing by odd numbers consecutively.
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or: n = the term number, the rule is: n2 or n(n). 12=1(1x1=1), 22=4(2x2=4), 32=9(3x3=9), and so on.
So you're adding 3, 5, 7, 9, 11 etc 1, 4, 9, 16, 25, 36, 49
4,9,16,25,36,49,64,81,100,121
2(x2=) 4 3(x3=) 9 4(x4=)16 the next numbers are 16 5 25 6 36
They are: 25 and 36
rule: add 18 to each number, starting with 18.
t(n) = n2
Yes
Yes.
no it is not a recursive pattern because it isn't equal numbers.
-16
add 3,5,7,9and then to 25 add 11, adding odd numbers onto the last . 1+3=4, 4+5=9, 9+7=16, 16+9=25, 25+11=36 and so on
The perfect squares in the range are 25, 36 and 49.
1, 4, 9, 16, 25, 36
The pattern is the squared numbers with the digits reversed. 92 = 81 → 18 82 = 64 → 46 72 = 49 → 94 62 = 36 → 63 52 = 25 → 52 42 = 16 → 61
These are the square numbers: 1, 4, 9, 16, 25, 36, 49, 64, 81...
assuming you mis-typed the 15 and instead it should be a 25, these are simply the squares of the number's position in the line. 12 = 1 22 = 2 32 = 9 42 = 16 52 = 25 (assume is what you meant) 62 = 36 You can also think of it as adding on the next in a series of odd numbers 1+3 = 4 4+5 = 9 9+7 = 16 which results from expanding (x+1)2 - x2 anyway
1, 4, 9, 16, 25, 36