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You must know the cross sectional area of the container. In this case you assume it is the same container so you can use a ratio/proportion.

13.0 is to 7.48 what X is to 12

13/7.48 :: X/12

cross multiply and divide

13 x 12 = 7.48 x X

156 = 7.48x

156/7.48 = X

X = 20.85

or (13/7.48)x12=20.85. where 12 is the height of the container

Q: 1ft3 is equal to 7.48 gal of liqued but what would 13.0 gal meashure 21 inches ft3?

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