10 mg/2 mg = 5 Five 2 mg warfarin pills would equal 10 milligrams of warfarin.
mg + CuCl2 + MgCl2 + Cu Mg + Cu^+2 = Mg^+2 + Cu
2000 mg = 2 g
1 gr = 1,000 mg 2 gr = 2,000 mg . . 5 gr = 5,000 mg
1 g = 1,000 mg 2 g = 2,000 mg 3 g = 3,000 mg . . . 100 g = 100,000 mg
Mg equals Mg2+ plus 2e-
2Mg(s) + O2(g) ==> 2MgOMg ===> Mg^2+ + 2e- [x2 to balance electrons] = oxidation half reactionO2 + 4e- ===> 2O^2-So, the final oxidation half reaction will be:2Mg(s) ===> 2Mg^2+ + 4e-
When Mg(OH)2 dissolves in water, it dissociates into magnesium ions (Mg2+) and hydroxide ions (OH-). Mg(OH)2 → Mg2+ + 2OH-
The ionic charge on "Mg2", presumably meaning the cation whose formula is Mg+2, is +2. In the unlikely event that "Mg2" means a diatomic molecule of elemental magnesium, the ionic charge would be 0,
Ionic bond: Mg2+ + 2 F- --> MgF2
Mg2+ and neon are isoelectronic
To form Mg2+, one electron is lost. Magnesium (Mg) normally has 12 electrons, but when it loses one electron to form Mg2+, it then has 11 electrons.
Ni2+(aq) + 2e- Ni(s) and Mg(s) Mg2+(aq) + 2e-
Mg is the symbol for the element magnesium and could be used to represent a neutral atom of magnesium. Mg2- does not occur, but Mg2+ does, and is the symbol of a magnesium ion, which is a magnesium atom that has lost two electrons.
Zn2+(aq) +2e- => Zn(s) and Mg(s) => Mg2+(aq) + 2e-
The answer is...1000 milligrams are in one gram.
The standard reduction potential E for the half-reaction Mg2+ + 2e- -> Mg is -2.37 V. This indicates the tendency of Mg^2+ ions to gain electrons and form Mg in a reduction reaction.