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I--2a+b=2c+2d II--2a+b=c+2d III--a+2b=3d * Here if we perform (I)-(II), we get, c=0 * Using the c we can prove b=0 using (I)-(III). * Now replace 'b' & 'c' as 0 in (I), then we get a=d. email me at for any queries. I will be very thankful to receive your queries.

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Q: 2a plus 1b equals 2c plus 2d-----2a plus 1b equals 1c plus 2d----- 1a plus 2b equals 3d-----what does 4a equal?
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