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well, this is pretty easy, just look at it logically:
2x - 2y + 5z - 2x - y + 3z
when you are trying to simplify a formula, your best practice would be to always begin with "organizing" the numbers, in this case it would become:
2x - 2x -2y - y + 5z +3z
when you organize it, it becomes clear what you need to do; first you get rid of the "opposing" values which cancel each other out, in this case the 2x:
2x - 2x -2y - y + 5z +3z = -2y - y + 5z + 3z
When two numbers have the exact same values but one is positive and the other is negative, their result is always zero, so you can simply erase them. In the opposite, when both of them are positive or both of them are negative, then they add up to each other:
-2y - y + 5z +3z = -3y + 8z OR 8z - 3y
For this one, I don't think it can be simplified further, 8z - 3y is its' simplest form.
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5x-2y plus 3z-2x-y-4z equals?
5x-2y+3z-2x-y-4z=3x-3y-z
How do you simplify an algebraic expression?
Ex. 5x-2y+3z-2x-y+4z Alright so this is how i do it: I circle all the ones that have the x as variables and are like terms. (you don't have to do this, but i find it helps and makes it go faster) So i would have circled 5x and -2x because the sign in front of the term is with the term. Then i would have added together the two terms and that would end up being 3x because 5x plus -2x is 3x. and i write 3x down below. then i would have gone to the next thing in the problem which would be the y's. -2y and -y. when added together it is -3y. so i write -3y below with 3x so it should be 3x-3y. Then i go to the z's. 3z and 4z. 3z+4z is 7z. so i write that below. so far it should be: 3x-3y+7z because 7z is positive. And that is your final answer because you can't simplify any more because they are not like terms.
What are the variables for 2x - 5y plus 3z equals -1?
x, y and z are the variables.
Solve this system of equations 5x plus 3y plus z equals -29 x-3y plus 2z equals 23 14x-2y plus 3z equals -18?
Solve this system of equations. 5x+3y+z=-29 x-3y+2z=23 14x-2y+3z=-18 Write the solution as an ordered triple.
How do you solve these equations by substitution 2x-5y plus 2z equals 16 3x plus 2y-3z equals -19 4x-3y plus 4z equals 18?
If you mean: 2x-5y+2z = 16 and 3x+2y-3z = -19 and 4x-3y+4z = 18 then the solutions are found as follows:- 3(2x-5y+2z = 16) => 6x-15y+6z = 48 2(3x+2y-3z = -19) => 6x+4y-6z = -38 Adding the above: 12x-11y = 10 thus eliminating z 4(3x+2y-3z = -19) => 12x+8y-12z = -76 3(4x-3y+4z = 18) => 12x-9y+12z = 54 Adding the above: 24x-y = -22 thus eliminating z 2(12x-11y = 10) => 24x-22y = 20 1(24x-y = -22) => 24x-y = -22 Subtracting the above: -21y = 42 thus eliminating x If: -21y = 42 then y = -2 So by substitution: x = -1, y = -2 and z = 4 Check: (2*-1)-(5*-2)+(2*4) = 16 Check: (3*-1)+(2*-2)-(3*4) = -19 Check: (4*-1)-(3*-2)+(4*4) = 18
