No, N2 + 3H2 -> 2NH is the formula to make Ammonia, a gas that is present in urine.
I think you mean mole ratio. It is usually represented as the coefficient or big number in a balanced chemical equation. N2 + 3H2 --> 2NH3 so the mole ratio of nitrogen to hydrogen is 1 : 3 or 1/3 and what you compare should be product / product or reactant / reactant
n x n = n2
n2-3n+2
In America it is math, in most European countries it is maths
Yes, math is called maths in Welsh.
2NH3 is the product of N2+3H2
The formula for the synthesis of ammonia from diatomic nitrogen and hydrogen is: N2+3H2-->2NH3
The balanced equation for this reaction is: N2(g) + 3H2(g) → 2NH3(g).
The balanced symbol equation for the formation of ammonia is: N2 + 3H2 → 2NH3
N2 + 3H2 ==> 2NH3
The equation for the formation of ammonia is: N2(g) + 3H2(g) -> 2NH3(g)
the haber process the haber process the equation is N2 + 3H2 <--> 2NH3 the haber process! its easy, the equation is N2 + 3H2 <--> 2NH3
The balanced equation for this reaction is: 3H2 + N2 -> 2NH3
The balanced equation for the production of ammonia is the following: N2 + 3H2 ---> 2NH3
3H2 + N2 --> 2NH3 Since Hydrogen (H) and Nitrogen (N) both appear in nature diatomically they only appear as H2 and N2. We must add 3 molecules of Hydrogen and 1 molecule of Nitrogen to get 2 molecules of ammonia. We cannot, in nature, have half of a diatomic Hydrogen or Nitrogen atom, for that reason the equation must yield 2 molecules of Ammonia.
The balanced equation for the reaction of hydrogen gas (H2) with nitrogen gas (N2) to form ammonia (NH3) is: 3H2 + N2 → 2NH3
The formula for the decomposition for ammonia would be 2NH3 --> N2 + 3H2