No, N2 + 3H2 -> 2NH is the formula to make Ammonia, a gas that is present in urine.
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I think you mean mole ratio. It is usually represented as the coefficient or big number in a balanced chemical equation. N2 + 3H2 --> 2NH3 so the mole ratio of nitrogen to hydrogen is 1 : 3 or 1/3 and what you compare should be product / product or reactant / reactant
n2 + n2 = 2 n2
n x n = n2
n2-3n+2
2NH3 is the product of N2+3H2
The formula for the synthesis of ammonia from diatomic nitrogen and hydrogen is: N2+3H2-->2NH3
N2 + 3H2 ==> 2NH3
N2 + 3H2 --> 2NH3 N2 + 3H2 --> 2NH3
the haber process the haber process the equation is N2 + 3H2 <--> 2NH3 the haber process! its easy, the equation is N2 + 3H2 <--> 2NH3
the haber process the haber process the equation is N2 + 3H2 <--> 2NH3 the haber process! its easy, the equation is N2 + 3H2 <--> 2NH3
N2 + 3h2
N2 + 3h2 ----> 2NH3
3H2 + N2 --> 2NH3 Since Hydrogen (H) and Nitrogen (N) both appear in nature diatomically they only appear as H2 and N2. We must add 3 molecules of Hydrogen and 1 molecule of Nitrogen to get 2 molecules of ammonia. We cannot, in nature, have half of a diatomic Hydrogen or Nitrogen atom, for that reason the equation must yield 2 molecules of Ammonia.
In the equation N2+3H2=2NH3, the amount of ammonia produced from 50g of N would be 16.667g.
Haber proces N2 + 3H2 = 2NH3
N2 + 3h2 ---> 2nh3