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I think you mean mole ratio. It is usually represented as the coefficient or big number in a balanced chemical equation. N2 + 3H2 --> 2NH3 so the mole ratio of nitrogen to hydrogen is 1 : 3 or 1/3 and what you compare should be product / product or reactant / reactant
n x n = n2
n2-3n+2
In America it is math, in most European countries it is maths
The chemical reaction between N2 and 3H2 produces 2NH3 molecules, which are ammonia.
The formula for the synthesis of ammonia from diatomic nitrogen and hydrogen is: N2+3H2-->2NH3
The balanced equation for this reaction is: N2(g) + 3H2(g) → 2NH3(g).
The balanced symbol equation for the formation of ammonia is: N2 + 3H2 → 2NH3
N2 + 3H2 ==> 2NH3
the haber process the haber process the equation is N2 + 3H2 <--> 2NH3 the haber process! its easy, the equation is N2 + 3H2 <--> 2NH3
The equation for the formation of ammonia is: N2(g) + 3H2(g) -> 2NH3(g)
The balanced equation for this reaction is: 3H2 + N2 -> 2NH3
The balanced equation for the formation of ammonia (NH3) from nitrogen gas (N2) and hydrogen gas (H2) is: N2 + 3H2 → 2NH3
3H2 + N2 --> 2NH3 Since Hydrogen (H) and Nitrogen (N) both appear in nature diatomically they only appear as H2 and N2. We must add 3 molecules of Hydrogen and 1 molecule of Nitrogen to get 2 molecules of ammonia. We cannot, in nature, have half of a diatomic Hydrogen or Nitrogen atom, for that reason the equation must yield 2 molecules of Ammonia.
The balanced equation for the reaction of hydrogen gas (H2) with nitrogen gas (N2) to form ammonia (NH3) is: 3H2 + N2 → 2NH3
The formula for the decomposition for ammonia would be 2NH3 --> N2 + 3H2