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What two consecutive does the side length of a square of an area of 90 square inches fall between?
9 inches and 10 inches.
If the length of one board is 2 feet 10 inches and the length of another board is 1 yard 1 foot 9 inches what is the total length of the two boards put together?
There are 3 feet in a yard and 12 inches in a foot. Convert all boards to the smallest unit (inches) 2 ft 10 inches = 34 inches 1 yard 1 foot and 9 inches = 57 inches 34 +57 = 91 inches, ( or 7 feet 7 inches), (or 2 yards 19 inches), ( or 2 yards 1 foot 7 inches)
If a strip of cloth 24 inches long will shrink to 22 inches when washed how many inches will a 36 inch strip be after shrinking?
Well, isn't that just a happy little problem to solve! If a 24-inch strip shrinks to 22 inches, that's a difference of 2 inches. So, for a 36-inch strip, you can expect it to shrink by the same proportion, which means it would shrink by 2/24 or 1/12 of its length. Therefore, a 36-inch strip would shrink by 3 inches, leaving you with a final length of 33 inches after washing. Happy shrinking!
What is the perimeter of a square whose sides measures 8.5 inches?
Perimeter of a figure is the sum of its side lengths. In a square, all four sides are the same length. So, the perimeter of a square whose side length is 8.5 is 4 x 8.5 = 34.
It takes ten identical pieces to form a circular track for a pair of toy racing cars If the inside of each piece is 3.4 inches shorter than the outside arc what is the width of the track?
Length of outer track = sum of length of 10 pieces = circumference of the outer circleif R is the Radius of outer circle then...Circumference of the outer track = 2pi*RSimilarly the circumference of the inner track (with radius r) = 2pi*rlength of each outer piece is 3.4 inch more than length of inner pieceSo total outer length is 10*3.4 =34 inches more than the inner length.=> Outer Circumference - Inner Circumference = 34 inches=> 2pi*R - 2pi*r = 34=> 2pi(R -r) = 34=> R-r = 34/2pi = 5.41 inches=> R-r = Width of the track = 5.41 inches1 year ago
