3x + 12 = x + 16
Take 12 away from each side of the equation, so...
3x = x + 4
Take x away from each side of the equation, so...
2x = 4
Divide each side of the equation by 2, so...
x = 2
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3x - 2 + 5 = 16 3x + 3 = 16 3x = 13 x = 13/3 ~ 4.333
y-3x+6y=12 7y=3x+12 y=3x/7 +12/7
3x + 2 = -10 3x = -12 x = -4
all you do is subtract the 3x from both sides and you get:y = -3x + 12
6-3x+12=0 6+12-3x=0 18-3x=0 18=3x x=6